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2390. Removing Stars From a String
Description
You are given a string s
, which contains stars *
.
In one operation, you can:
- Choose a star in
s
. - Remove the closest non-star character to its left, as well as remove the star itself.
Return the string after all stars have been removed.
Note:
- The input will be generated such that the operation is always possible.
- It can be shown that the resulting string will always be unique.
Example 1:
Input: s = "leet**cod*e" Output: "lecoe" Explanation: Performing the removals from left to right: - The closest character to the 1st star is 't' in "leet**cod*e". s becomes "lee*cod*e". - The closest character to the 2nd star is 'e' in "lee*cod*e". s becomes "lecod*e". - The closest character to the 3rd star is 'd' in "lecod*e". s becomes "lecoe". There are no more stars, so we return "lecoe".
Example 2:
Input: s = "erase*****" Output: "" Explanation: The entire string is removed, so we return an empty string.
Constraints:
1 <= s.length <= 105
s
consists of lowercase English letters and stars*
.- The operation above can be performed on
s
.
Solutions
-
class Solution { public String removeStars(String s) { StringBuilder ans = new StringBuilder(); for (int i = 0; i < s.length(); ++i) { if (s.charAt(i) == '*') { ans.deleteCharAt(ans.length() - 1); } else { ans.append(s.charAt(i)); } } return ans.toString(); } }
-
class Solution { public: string removeStars(string s) { string ans; for (char c : s) { if (c == '*') { ans.pop_back(); } else { ans.push_back(c); } } return ans; } };
-
class Solution: def removeStars(self, s: str) -> str: ans = [] for c in s: if c == '*': ans.pop() else: ans.append(c) return ''.join(ans)
-
func removeStars(s string) string { ans := []rune{} for _, c := range s { if c == '*' { ans = ans[:len(ans)-1] } else { ans = append(ans, c) } } return string(ans) }
-
function removeStars(s: string): string { const ans: string[] = []; for (const c of s) { if (c === '*') { ans.pop(); } else { ans.push(c); } } return ans.join(''); }
-
class Solution { /** * @param String $s * @return String */ function removeStars($s) { $rs = []; for ($i = 0; $i < strlen($s); $i++) { if ($s[$i] == '*') { array_pop($rs); } else { array_push($rs, $s[$i]); } } return join($rs); } }
-
impl Solution { pub fn remove_stars(s: String) -> String { let mut ans = String::new(); for &c in s.as_bytes().iter() { if c == b'*' { ans.pop(); } else { ans.push(char::from(c)); } } ans } }