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2315. Count Asterisks

Description

You are given a string s, where every two consecutive vertical bars '|' are grouped into a pair. In other words, the 1^st and 2^nd '|' make a pair, the 3^rd and 4^th '|' make a pair, and so forth.

Return the number of '*' in s, excluding the '*' between each pair of '|'.

Note that each '|' will belong to exactly one pair.

 

Example 1:

Input: s = "l|*e*et|c**o|*de|"
Output: 2
Explanation: The considered characters are underlined: "l|*e*et|c**o|*de|".
The characters between the first and second '|' are excluded from the answer.
Also, the characters between the third and fourth '|' are excluded from the answer.
There are 2 asterisks considered. Therefore, we return 2.

Example 2:

Input: s = "iamprogrammer"
Output: 0
Explanation: In this example, there are no asterisks in s. Therefore, we return 0.

Example 3:

Input: s = "yo|uar|e**|b|e***au|tifu|l"
Output: 5
Explanation: The considered characters are underlined: "yo|uar|e**|b|e***au|tifu|l". There are 5 asterisks considered. Therefore, we return 5.

 

Constraints:

• 1 <= s.length <= 1000
• s consists of lowercase English letters, vertical bars '|', and asterisks '*'.
• s contains an even number of vertical bars '|'.

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• C#
• RenderScript

• class Solution {
      public int countAsterisks(String s) {
          int ans = 0;
          for (int i = 0, ok = 1; i < s.length(); ++i) {
              char c = s.charAt(i);
              if (c == '*') {
                  ans += ok;
              } else if (c == '|') {
                  ok ^= 1;
              }
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      int countAsterisks(string s) {
          int ans = 0, ok = 1;
          for (char& c : s) {
              if (c == '*') {
                  ans += ok;
              } else if (c == '|') {
                  ok ^= 1;
              }
          }
          return ans;
      }
  };
  

• class Solution:
      def countAsterisks(self, s: str) -> int:
          ans, ok = 0, 1
          for c in s:
              if c == "*":
                  ans += ok
              elif c == "|":
                  ok ^= 1
          return ans
  
  

• func countAsterisks(s string) (ans int) {
  	ok := 1
  	for _, c := range s {
  		if c == '*' {
  			ans += ok
  		} else if c == '|' {
  			ok ^= 1
  		}
  	}
  	return
  }
  

• function countAsterisks(s: string): number {
      let ans = 0;
      let ok = 1;
      for (const c of s) {
          if (c === '*') {
              ans += ok;
          } else if (c === '|') {
              ok ^= 1;
          }
      }
      return ans;
  }
  
  

• public class Solution {
      public int CountAsterisks(string s) {
          int ans = 0, ok = 1;
          foreach (char c in s) {
              if (c == '*') {
                  ans += ok;
              } else if (c == '|') {
                  ok ^= 1;
              }
          }
          return ans;
      }
  }
  
  

• impl Solution {
      pub fn count_asterisks(s: String) -> i32 {
          let mut ans = 0;
          let mut ok = 1;
          for &c in s.as_bytes() {
              if c == b'*' {
                  ans += ok;
              } else if c == b'|' {
                  ok ^= 1;
              }
          }
          ans
      }
  }
  
  

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