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2311. Longest Binary Subsequence Less Than or Equal to K

Description

You are given a binary string s and a positive integer k.

Return the length of the longest subsequence of s that makes up a binary number less than or equal to k.

Note:

  • The subsequence can contain leading zeroes.
  • The empty string is considered to be equal to 0.
  • A subsequence is a string that can be derived from another string by deleting some or no characters without changing the order of the remaining characters.

 

Example 1:

Input: s = "1001010", k = 5
Output: 5
Explanation: The longest subsequence of s that makes up a binary number less than or equal to 5 is "00010", as this number is equal to 2 in decimal.
Note that "00100" and "00101" are also possible, which are equal to 4 and 5 in decimal, respectively.
The length of this subsequence is 5, so 5 is returned.

Example 2:

Input: s = "00101001", k = 1
Output: 6
Explanation: "000001" is the longest subsequence of s that makes up a binary number less than or equal to 1, as this number is equal to 1 in decimal.
The length of this subsequence is 6, so 6 is returned.

 

Constraints:

  • 1 <= s.length <= 1000
  • s[i] is either '0' or '1'.
  • 1 <= k <= 109

Solutions

  • class Solution {
    public int longestSubsequence(String s, int k) {
        int ans = 0, v = 0;
        for (int i = s.length() - 1; i >= 0; --i) {
            if (s.charAt(i) == '0') {
                ++ans;
            } else if (ans < 30 && (v | 1 << ans) <= k) {
                v |= 1 << ans;
                ++ans;
            }
        }
        return ans;
    }
}

  • class Solution {
public:
    int longestSubsequence(string s, int k) {
        int ans = 0, v = 0;
        for (int i = s.size() - 1; ~i; --i) {
            if (s[i] == '0') {
                ++ans;
            } else if (ans < 30 && (v | 1 << ans) <= k) {
                v |= 1 << ans;
                ++ans;
            }
        }
        return ans;
    }
};

  • class Solution:
    def longestSubsequence(self, s: str, k: int) -> int:
        ans = v = 0
        for c in s[::-1]:
            if c == "0":
                ans += 1
            elif ans < 30 and (v | 1 << ans) <= k:
                v |= 1 << ans
                ans += 1
        return ans


  • func longestSubsequence(s string, k int) (ans int) {
	for i, v := len(s)-1, 0; i >= 0; i-- {
		if s[i] == '0' {
			ans++
		} else if ans < 30 && (v|1<<ans) <= k {
			v |= 1 << ans
			ans++
		}
	}
	return
}

  • function longestSubsequence(s: string, k: number): number {
    let ans = 0;
    for (let i = s.length - 1, v = 0; ~i; --i) {
        if (s[i] == '0') {
            ++ans;
        } else if (ans < 30 && (v | (1 << ans)) <= k) {
            v |= 1 << ans;
            ++ans;
        }
    }
    return ans;
}


  • /**
 * @param {string} s
 * @param {number} k
 * @return {number}
 */
var longestSubsequence = function (s, k) {
    let ans = 0;
    for (let i = s.length - 1, v = 0; ~i; --i) {
        if (s[i] == '0') {
            ++ans;
        } else if (ans < 30 && (v | (1 << ans)) <= k) {
            v |= 1 << ans;
            ++ans;
        }
    }
    return ans;
};


  • public class Solution {
    public int LongestSubsequence(string s, int k) {
        int ans = 0, v = 0;
        for (int i = s.Length - 1; i >= 0; --i) {
            if (s[i] == '0') {
                ++ans;
            } else if (ans < 30 && (v | 1 << ans) <= k) {
                v |= 1 << ans;
                ++ans;
            }
        }
        return ans;
    }
}

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