Formatted question description: https://leetcode.ca/all/2150.html

2150. Find All Lonely Numbers in the Array (Medium)

You are given an integer array nums. A number x is lonely when it appears only once, and no adjacent numbers (i.e. x + 1 and x - 1) appear in the array.

Return all lonely numbers in nums. You may return the answer in any order.

 

Example 1:

Input: nums = [10,6,5,8]
Output: [10,8]
Explanation: 
- 10 is a lonely number since it appears exactly once and 9 and 11 does not appear in nums.
- 8 is a lonely number since it appears exactly once and 7 and 9 does not appear in nums.
- 5 is not a lonely number since 6 appears in nums and vice versa.
Hence, the lonely numbers in nums are [10, 8].
Note that [8, 10] may also be returned.

Example 2:

Input: nums = [1,3,5,3]
Output: [1,5]
Explanation: 
- 1 is a lonely number since it appears exactly once and 0 and 2 does not appear in nums.
- 5 is a lonely number since it appears exactly once and 4 and 6 does not appear in nums.
- 3 is not a lonely number since it appears twice.
Hence, the lonely numbers in nums are [1, 5].
Note that [5, 1] may also be returned.

 

Constraints:

  • 1 <= nums.length <= 105
  • 0 <= nums[i] <= 106

Similar Questions:

Solution 1. Hash Map

  • // OJ: https://leetcode.com/problems/find-all-lonely-numbers-in-the-array/
    // Time: O(N)
    // Space: O(U) where U is the number of unique elements in `A`
    class Solution {
    public:
        vector<int> findLonely(vector<int>& A) {
            unordered_map<int, int> m;
            for (int n : A) m[n]++;
            vector<int> ans;
            for (int n : A) {
                if (m[n] == 1 && m.count(n + 1) == 0 && m.count(n - 1) == 0) {
                    ans.push_back(n);
                }
            }
            return ans;
        }
    };
    
  • // Todo
    
  • # 2150. Find All Lonely Numbers in the Array
    # https://leetcode.com/problems/find-all-lonely-numbers-in-the-array/
    
    class Solution:
        def findLonely(self, nums: List[int]) -> List[int]:
            counter = Counter(nums)
            res = []
            
            for x in counter.keys():
                if counter[x] == 1 and x - 1 not in counter and x + 1 not in counter:
                    res.append(x)
            
            return res
    
    

Discuss

https://leetcode.com/problems/find-all-lonely-numbers-in-the-array/discuss/1711230/C%2B%2B-Hash-Map-O(N)

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