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2227. Encrypt and Decrypt Strings
Description
You are given a character array keys
containing unique characters and a string array values
containing strings of length 2. You are also given another string array dictionary
that contains all permitted original strings after decryption. You should implement a data structure that can encrypt or decrypt a 0-indexed string.
A string is encrypted with the following process:
- For each character
c
in the string, we find the indexi
satisfyingkeys[i] == c
inkeys
. - Replace
c
withvalues[i]
in the string.
Note that in case a character of the string is not present in keys
, the encryption process cannot be carried out, and an empty string ""
is returned.
A string is decrypted with the following process:
- For each substring
s
of length 2 occurring at an even index in the string, we find ani
such thatvalues[i] == s
. If there are multiple validi
, we choose any one of them. This means a string could have multiple possible strings it can decrypt to. - Replace
s
withkeys[i]
in the string.
Implement the Encrypter
class:
Encrypter(char[] keys, String[] values, String[] dictionary)
Initializes theEncrypter
class withkeys, values
, anddictionary
.String encrypt(String word1)
Encryptsword1
with the encryption process described above and returns the encrypted string.int decrypt(String word2)
Returns the number of possible stringsword2
could decrypt to that also appear indictionary
.
Example 1:
Input ["Encrypter", "encrypt", "decrypt"] [[['a', 'b', 'c', 'd'], ["ei", "zf", "ei", "am"], ["abcd", "acbd", "adbc", "badc", "dacb", "cadb", "cbda", "abad"]], ["abcd"], ["eizfeiam"]] Output [null, "eizfeiam", 2] Explanation Encrypter encrypter = new Encrypter([['a', 'b', 'c', 'd'], ["ei", "zf", "ei", "am"], ["abcd", "acbd", "adbc", "badc", "dacb", "cadb", "cbda", "abad"]); encrypter.encrypt("abcd"); // return "eizfeiam". // 'a' maps to "ei", 'b' maps to "zf", 'c' maps to "ei", and 'd' maps to "am". encrypter.decrypt("eizfeiam"); // return 2. // "ei" can map to 'a' or 'c', "zf" maps to 'b', and "am" maps to 'd'. // Thus, the possible strings after decryption are "abad", "cbad", "abcd", and "cbcd". // 2 of those strings, "abad" and "abcd", appear in dictionary, so the answer is 2.
Constraints:
1 <= keys.length == values.length <= 26
values[i].length == 2
1 <= dictionary.length <= 100
1 <= dictionary[i].length <= 100
- All
keys[i]
anddictionary[i]
are unique. 1 <= word1.length <= 2000
1 <= word2.length <= 200
- All
word1[i]
appear inkeys
. word2.length
is even.keys
,values[i]
,dictionary[i]
,word1
, andword2
only contain lowercase English letters.- At most
200
calls will be made toencrypt
anddecrypt
in total.
Solutions
-
class Encrypter { private Map<Character, String> mp = new HashMap<>(); private Map<String, Integer> cnt = new HashMap<>(); public Encrypter(char[] keys, String[] values, String[] dictionary) { for (int i = 0; i < keys.length; ++i) { mp.put(keys[i], values[i]); } for (String w : dictionary) { w = encrypt(w); cnt.put(w, cnt.getOrDefault(w, 0) + 1); } } public String encrypt(String word1) { StringBuilder sb = new StringBuilder(); for (char c : word1.toCharArray()) { if (!mp.containsKey(c)) { return ""; } sb.append(mp.get(c)); } return sb.toString(); } public int decrypt(String word2) { return cnt.getOrDefault(word2, 0); } } /** * Your Encrypter object will be instantiated and called as such: * Encrypter obj = new Encrypter(keys, values, dictionary); * String param_1 = obj.encrypt(word1); * int param_2 = obj.decrypt(word2); */
-
class Encrypter { public: unordered_map<string, int> cnt; unordered_map<char, string> mp; Encrypter(vector<char>& keys, vector<string>& values, vector<string>& dictionary) { for (int i = 0; i < keys.size(); ++i) mp[keys[i]] = values[i]; for (auto v : dictionary) cnt[encrypt(v)]++; } string encrypt(string word1) { string res = ""; for (char c : word1) { if (!mp.count(c)) return ""; res += mp[c]; } return res; } int decrypt(string word2) { return cnt[word2]; } }; /** * Your Encrypter object will be instantiated and called as such: * Encrypter* obj = new Encrypter(keys, values, dictionary); * string param_1 = obj->encrypt(word1); * int param_2 = obj->decrypt(word2); */
-
class Encrypter: def __init__(self, keys: List[str], values: List[str], dictionary: List[str]): self.mp = dict(zip(keys, values)) self.cnt = Counter(self.encrypt(v) for v in dictionary) def encrypt(self, word1: str) -> str: res = [] for c in word1: if c not in self.mp: return '' res.append(self.mp[c]) return ''.join(res) def decrypt(self, word2: str) -> int: return self.cnt[word2] # Your Encrypter object will be instantiated and called as such: # obj = Encrypter(keys, values, dictionary) # param_1 = obj.encrypt(word1) # param_2 = obj.decrypt(word2)
-
type Encrypter struct { mp map[byte]string cnt map[string]int } func Constructor(keys []byte, values []string, dictionary []string) Encrypter { mp := map[byte]string{} cnt := map[string]int{} for i, k := range keys { mp[k] = values[i] } e := Encrypter{mp, cnt} for _, v := range dictionary { e.cnt[e.Encrypt(v)]++ } return e } func (this *Encrypter) Encrypt(word1 string) string { var ans strings.Builder for _, c := range word1 { if v, ok := this.mp[byte(c)]; ok { ans.WriteString(v) } else { return "" } } return ans.String() } func (this *Encrypter) Decrypt(word2 string) int { return this.cnt[word2] } /** * Your Encrypter object will be instantiated and called as such: * obj := Constructor(keys, values, dictionary); * param_1 := obj.Encrypt(word1); * param_2 := obj.Decrypt(word2); */