# 2169. Count Operations to Obtain Zero

## Description

You are given two non-negative integers num1 and num2.

In one operation, if num1 >= num2, you must subtract num2 from num1, otherwise subtract num1 from num2.

• For example, if num1 = 5 and num2 = 4, subtract num2 from num1, thus obtaining num1 = 1 and num2 = 4. However, if num1 = 4 and num2 = 5, after one operation, num1 = 4 and num2 = 1.

Return the number of operations required to make either num1 = 0 or num2 = 0.

Example 1:

Input: num1 = 2, num2 = 3
Output: 3
Explanation:
- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.


Example 2:

Input: num1 = 10, num2 = 10
Output: 1
Explanation:
- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.


Constraints:

• 0 <= num1, num2 <= 105

## Solutions

• class Solution {
public int countOperations(int num1, int num2) {
int ans = 0;
while (num1 != 0 && num2 != 0) {
if (num1 >= num2) {
num1 -= num2;
} else {
num2 -= num1;
}
++ans;
}
return ans;
}
}

• class Solution {
public:
int countOperations(int num1, int num2) {
int ans = 0;
while (num1 && num2) {
if (num1 > num2) swap(num1, num2);
num2 -= num1;
++ans;
}
return ans;
}
};

• class Solution:
def countOperations(self, num1: int, num2: int) -> int:
ans = 0
while num1 and num2:
if num1 >= num2:
num1, num2 = num2, num1
num2 -= num1
ans += 1
return ans


• func countOperations(num1 int, num2 int) int {
ans := 0
for num1 != 0 && num2 != 0 {
if num1 > num2 {
num1, num2 = num2, num1
}
num2 -= num1
ans++
}
return ans
}

• function countOperations(num1: number, num2: number): number {
let ans = 0;
while (num1 && num2) {
[num1, num2] = [Math.min(num1, num2), Math.abs(num1 - num2)];
ans++;
}
return ans;
}