Formatted question description: https://leetcode.ca/all/2037.html

2037. Minimum Number of Moves to Seat Everyone (Easy)

There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student.

You may perform the following move any number of times:

  • Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)

Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.

Note that there may be multiple seats or students in the same position at the beginning.

 

Example 1:

Input: seats = [3,1,5], students = [2,7,4]
Output: 4
Explanation: The students are moved as follows:
- The first student is moved from from position 2 to position 1 using 1 move.
- The second student is moved from from position 7 to position 5 using 2 moves.
- The third student is moved from from position 4 to position 3 using 1 move.
In total, 1 + 2 + 1 = 4 moves were used.

Example 2:

Input: seats = [4,1,5,9], students = [1,3,2,6]
Output: 7
Explanation: The students are moved as follows:
- The first student is not moved.
- The second student is moved from from position 3 to position 4 using 1 move.
- The third student is moved from from position 2 to position 5 using 3 moves.
- The fourth student is moved from from position 6 to position 9 using 3 moves.
In total, 0 + 1 + 3 + 3 = 7 moves were used.

Example 3:

Input: seats = [2,2,6,6], students = [1,3,2,6]
Output: 4
Explanation: The students are moved as follows:
- The first student is moved from from position 1 to position 2 using 1 move.
- The second student is moved from from position 3 to position 6 using 3 moves.
- The third student is not moved.
- The fourth student is not moved.
In total, 1 + 3 + 0 + 0 = 4 moves were used.

 

Constraints:

  • n == seats.length == students.length
  • 1 <= n <= 100
  • 1 <= seats[i], students[j] <= 100

Solution 1. Sorting

Sort both arrays. Match each seat to the corresponding student with the same index with abs(seats[i] - students[i]) moves.

// OJ: https://leetcode.com/problems/minimum-number-of-moves-to-seat-everyone/
// Time: O(NlogN)
// Space: O(1)
class Solution {
public:
    int minMovesToSeat(vector<int>& A, vector<int>& B) {
        sort(begin(A), end(A));
        sort(begin(B), end(B));
        int ans = 0;
        for (int i = 0; i < A.size(); ++i) {
            ans += abs(A[i] - B[i]);
        }
        return ans;
    }
};

Discuss

https://leetcode.com/problems/minimum-number-of-moves-to-seat-everyone/discuss/1524331/C%2B%2B-Sorting

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