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2109. Adding Spaces to a String

Description

You are given a 0-indexed string s and a 0-indexed integer array spaces that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.

  • For example, given s = "EnjoyYourCoffee" and spaces = [5, 9], we place spaces before 'Y' and 'C', which are at indices 5 and 9 respectively. Thus, we obtain "Enjoy Your Coffee".

Return the modified string after the spaces have been added.

 

Example 1:

Input: s = "LeetcodeHelpsMeLearn", spaces = [8,13,15]
Output: "Leetcode Helps Me Learn"
Explanation: 
The indices 8, 13, and 15 correspond to the underlined characters in "LeetcodeHelpsMeLearn".
We then place spaces before those characters.

Example 2:

Input: s = "icodeinpython", spaces = [1,5,7,9]
Output: "i code in py thon"
Explanation:
The indices 1, 5, 7, and 9 correspond to the underlined characters in "icodeinpython".
We then place spaces before those characters.

Example 3:

Input: s = "spacing", spaces = [0,1,2,3,4,5,6]
Output: " s p a c i n g"
Explanation:
We are also able to place spaces before the first character of the string.

 

Constraints:

  • 1 <= s.length <= 3 * 105
  • s consists only of lowercase and uppercase English letters.
  • 1 <= spaces.length <= 3 * 105
  • 0 <= spaces[i] <= s.length - 1
  • All the values of spaces are strictly increasing.

Solutions

  • class Solution {
        public String addSpaces(String s, int[] spaces) {
            StringBuilder ans = new StringBuilder();
            for (int i = 0, j = 0; i < s.length(); ++i) {
                if (j < spaces.length && i == spaces[j]) {
                    ans.append(' ');
                    ++j;
                }
                ans.append(s.charAt(i));
            }
            return ans.toString();
        }
    }
    
  • class Solution {
    public:
        string addSpaces(string s, vector<int>& spaces) {
            string ans = "";
            for (int i = 0, j = 0; i < s.size(); ++i) {
                if (j < spaces.size() && i == spaces[j]) {
                    ans += ' ';
                    ++j;
                }
                ans += s[i];
            }
            return ans;
        }
    };
    
  • class Solution:
        def addSpaces(self, s: str, spaces: List[int]) -> str:
            ans = []
            j = 0
            for i, c in enumerate(s):
                if j < len(spaces) and i == spaces[j]:
                    ans.append(' ')
                    j += 1
                ans.append(c)
            return ''.join(ans)
    
    
  • func addSpaces(s string, spaces []int) string {
    	var ans []byte
    	for i, j := 0, 0; i < len(s); i++ {
    		if j < len(spaces) && i == spaces[j] {
    			ans = append(ans, ' ')
    			j++
    		}
    		ans = append(ans, s[i])
    	}
    	return string(ans)
    }
    
  • function addSpaces(s: string, spaces: number[]): string {
        let ans = '';
        for (let i = 0, j = 0; i < s.length; i++) {
            if (j < spaces.length && i === spaces[j]) {
                ans += ' ';
                ++j;
            }
            ans += s[i];
        }
        return ans;
    }
    
    

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