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Formatted question description: https://leetcode.ca/all/1979.html
1979. Find Greatest Common Divisor of Array
Level
Easy
Description
Given an integer array nums, return the greatest common divisor of the smallest number and largest number in nums.
The greatest common divisor of two numbers is the largest positive integer that evenly divides both numbers.
Example 1:
Input: nums = [2,5,6,9,10]
Output: 2
Explanation:
The smallest number in nums is 2.
The largest number in nums is 10.
The greatest common divisor of 2 and 10 is 2.
Example 2:
Input: nums = [7,5,6,8,3]
Output: 1
Explanation:
The smallest number in nums is 3.
The largest number in nums is 8.
The greatest common divisor of 3 and 8 is 1.
Example 3:
Input: nums = [3,3]
Output: 3
Explanation:
The smallest number in nums is 3.
The largest number in nums is 3.
The greatest common divisor of 3 and 3 is 3.
Constraints:
2 <= nums.length <= 10001 <= nums[i] <= 1000
Solution
Get the smallest number and the largest number in nums and calculate the greatest common divisor.
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class Solution { public int findGCD(int[] nums) { Arrays.sort(nums); int minNum = nums[0], maxNum = nums[nums.length - 1]; return gcd(minNum, maxNum); } public int gcd(int a, int b) { if (a > b) { int temp = a; a = b; b = temp; } if (b % a == 0) return a; return gcd(a, b % a); } } ############ class Solution { public int findGCD(int[] nums) { int a = 1, b = 1000; for (int x : nums) { a = Math.max(a, x); b = Math.min(b, x); } return gcd(a, b); } private int gcd(int a, int b) { return b == 0 ? a : gcd(b, a % b); } } -
// OJ: https://leetcode.com/problems/find-greatest-common-divisor-of-array/ // Time: O(N) // Space: O(1) class Solution { public: int findGCD(vector<int>& A) { return gcd(*min_element(begin(A), end(A)), *max_element(begin(A), end(A))); } }; -
class Solution: def findGCD(self, nums: List[int]) -> int: return gcd(max(nums), min(nums)) ############ # 1979. Find Greatest Common Divisor of Array # https://leetcode.com/problems/find-greatest-common-divisor-of-array/ class Solution: def findGCD(self, nums: List[int]) -> int: return gcd(max(nums), min(nums)) -
func findGCD(nums []int) int { a, b := 1, 1000 for _, x := range nums { if a < x { a = x } if b > x { b = x } } return gcd(a, b) } func gcd(a, b int) int { if b == 0 { return a } return gcd(b, a%b) } -
function findGCD(nums: number[]): number { let a = 1; let b = 1000; for (const x of nums) { a = Math.max(a, x); b = Math.min(b, x); } return gcd(a, b); } function gcd(a: number, b: number): number { if (b == 0) { return a; } return gcd(b, a % b); }