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Formatted question description: https://leetcode.ca/all/1967.html

1967. Number of Strings That Appear as Substrings in Word

Level

Easy

Description

Given an array of strings patterns and a string word, return the number of strings in patterns that exist as a substring in word.

A substring is a contiguous sequence of characters within a string.

Example 1:

Input: patterns = [“a”,”abc”,”bc”,”d”], word = “abc”

Output: 3

Explanation:

  • “a” appears as a substring in “abc”.
  • “abc” appears as a substring in “abc”.
  • “bc” appears as a substring in “abc”.
  • “d” does not appear as a substring in “abc”.

3 of the strings in patterns appear as a substring in word.

Example 2:

Input: patterns = [“a”,”b”,”c”], word = “aaaaabbbbb”

Output: 2

Explanation:

  • “a” appears as a substring in “aaaaabbbbb”.
  • “b” appears as a substring in “aaaaabbbbb”.
  • “c” does not appear as a substring in “aaaaabbbbb”.

2 of the strings in patterns appear as a substring in word.

Example 3:

Input: patterns = [“a”,”a”,”a”], word = “ab”

Output: 3

Explanation: Each of the patterns appears as a substring in word “ab”.

Constraints:

  • 1 <= patterns.length <= 100
  • 1 <= patterns[i].length <= 100
  • 1 <= word.length <= 100
  • patterns[i] and word consist of lowercase English letters.

Solution

Loop over patterns and for each element in pattern, check whether it is a substring of word. Return the number of elements that are substrings of word.

  • class Solution {
        public int numOfStrings(String[] patterns, String word) {
            int count = 0;
            for (String pattern : patterns) {
                if (word.indexOf(pattern) >= 0)
                    count++;
            }
            return count;
        }
    }
    
    ############
    
    class Solution {
        public int numOfStrings(String[] patterns, String word) {
            int ans = 0;
            for (String p : patterns) {
                if (word.contains(p)) {
                    ++ans;
                }
            }
            return ans;
        }
    }
    
  • // OJ: https://leetcode.com/problems/number-of-strings-that-appear-as-substrings-in-word/
    // Time: O(MN)
    // Space: O(1)
    class Solution {
    public:
        int numOfStrings(vector<string>& A, string word) {
            int ans = 0;
            for (auto &s : A) {
                if (word.find(s) != string::npos) ++ans;
            }
            return ans;
        }
    };
    
  • class Solution:
        def numOfStrings(self, patterns: List[str], word: str) -> int:
            return sum(1 for p in patterns if p in word)
    
    ############
    
    # 1967. Number of Strings That Appear as Substrings in Word
    # https://leetcode.com/problems/number-of-strings-that-appear-as-substrings-in-word/
    
    class Solution:
        def numOfStrings(self, patterns: List[str], word: str) -> int:
            res = 0
            
            for p in patterns:
                if p in word:
                    res += 1
            
            return res
    
    
  • func numOfStrings(patterns []string, word string) (ans int) {
    	for _, p := range patterns {
    		if strings.Contains(word, p) {
    			ans++
    		}
    	}
    	return
    }
    
  • function numOfStrings(patterns: string[], word: string): number {
        let ans = 0;
        for (const p of patterns) {
            if (word.includes(p)) {
                ++ans;
            }
        }
        return ans;
    }
    
    

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