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Formatted question description: https://leetcode.ca/all/1967.html

1967. Number of Strings That Appear as Substrings in Word

Level

Easy

Description

Given an array of strings patterns and a string word, return the number of strings in patterns that exist as a substring in word.

A substring is a contiguous sequence of characters within a string.

Example 1:

Input: patterns = [“a”,”abc”,”bc”,”d”], word = “abc”

Output: 3

Explanation:

• “a” appears as a substring in “abc”.
• “abc” appears as a substring in “abc”.
• “bc” appears as a substring in “abc”.
• “d” does not appear as a substring in “abc”.

3 of the strings in patterns appear as a substring in word.

Example 2:

Input: patterns = [“a”,”b”,”c”], word = “aaaaabbbbb”

Output: 2

Explanation:

• “a” appears as a substring in “aaaaabbbbb”.
• “b” appears as a substring in “aaaaabbbbb”.
• “c” does not appear as a substring in “aaaaabbbbb”.

2 of the strings in patterns appear as a substring in word.

Example 3:

Input: patterns = [“a”,”a”,”a”], word = “ab”

Output: 3

Explanation: Each of the patterns appears as a substring in word “ab”.

Constraints:

• 1 <= patterns.length <= 100
• 1 <= patterns[i].length <= 100
• 1 <= word.length <= 100
• patterns[i] and word consist of lowercase English letters.

Solution

Loop over patterns and for each element in pattern, check whether it is a substring of word. Return the number of elements that are substrings of word.

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public int numOfStrings(String[] patterns, String word) {
          int count = 0;
          for (String pattern : patterns) {
              if (word.indexOf(pattern) >= 0)
                  count++;
          }
          return count;
      }
  }
  
  ############
  
  class Solution {
      public int numOfStrings(String[] patterns, String word) {
          int ans = 0;
          for (String p : patterns) {
              if (word.contains(p)) {
                  ++ans;
              }
          }
          return ans;
      }
  }
  

• // OJ: https://leetcode.com/problems/number-of-strings-that-appear-as-substrings-in-word/
  // Time: O(MN)
  // Space: O(1)
  class Solution {
  public:
      int numOfStrings(vector<string>& A, string word) {
          int ans = 0;
          for (auto &s : A) {
              if (word.find(s) != string::npos) ++ans;
          }
          return ans;
      }
  };
  

• class Solution:
      def numOfStrings(self, patterns: List[str], word: str) -> int:
          return sum(1 for p in patterns if p in word)
  
  ############
  
  # 1967. Number of Strings That Appear as Substrings in Word
  # https://leetcode.com/problems/number-of-strings-that-appear-as-substrings-in-word/
  
  class Solution:
      def numOfStrings(self, patterns: List[str], word: str) -> int:
          res = 0
          
          for p in patterns:
              if p in word:
                  res += 1
          
          return res
  
  

• func numOfStrings(patterns []string, word string) (ans int) {
  	for _, p := range patterns {
  		if strings.Contains(word, p) {
  			ans++
  		}
  	}
  	return
  }
  

• function numOfStrings(patterns: string[], word: string): number {
      let ans = 0;
      for (const p of patterns) {
          if (word.includes(p)) {
              ++ans;
          }
      }
      return ans;
  }
  
  

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