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Formatted question description: https://leetcode.ca/all/1860.html

1860. Incremental Memory Leak

Level

Medium

Description

You are given two integers memory1 and memory2 representing the available memory in bits on two memory sticks. There is currently a faulty program running that consumes an increasing amount of memory every second.

At the i-th second (starting from 1), i bits of memory are allocated to the stick with more available memory (or from the first memory stick if both have the same available memory). If neither stick has at least i bits of available memory, the program crashes.

Return an array containing [crashTime, memory1_crash, memory2_crash], where crashTime is the time (in seconds) when the program crashed and memory1_crash and memory2_crash are the available bits of memory in the first and second sticks respectively.

Example 1:

Input: memory1 = 2, memory2 = 2

Output: [3,1,0]

Explanation: The memory is allocated as follows:

  • At the 1st second, 1 bit of memory is allocated to stick 1. The first stick now has 1 bit of available memory.
  • At the 2nd second, 2 bits of memory are allocated to stick 2. The second stick now has 0 bits of available memory.
  • At the 3rd second, the program crashes. The sticks have 1 and 0 bits available respectively.

Example 2:

Input: memory1 = 8, memory2 = 11

Output: [6,0,4]

Explanation: The memory is allocated as follows:

  • At the 1st second, 1 bit of memory is allocated to stick 2. The second stick now has 10 bit of available memory.
  • At the 2nd second, 2 bits of memory are allocated to stick 2. The second stick now has 8 bits of available memory.
  • At the 3rd second, 3 bits of memory are allocated to stick 1. The first stick now has 5 bits of available memory.
  • At the 4th second, 4 bits of memory are allocated to stick 2. The second stick now has 4 bits of available memory.
  • At the 5th second, 5 bits of memory are allocated to stick 1. The first stick now has 0 bits of available memory.
  • At the 6th second, the program crashes. The sticks have 0 and 4 bits available respectively.

Constraints:

  • 0 <= memory1, memory2 <= 2^31 - 1

Solution

Simulate the process. Maintain a variable time with initial value 0. Each time increase time by 1 and update either memory1 or memory2. Once both memory1 and memory2 are less than time, the program crashes, so return the array [time, memory1, memory2].

  • class Solution {
        public int[] memLeak(int memory1, int memory2) {
            int time = 0;
            boolean flag = true;
            while (flag) {
                time++;
                if (memory1 < time && memory2 < time)
                    flag = false;
                else {
                    if (memory1 >= memory2)
                        memory1 -= time;
                    else
                        memory2 -= time;
                }
            }
            return new int[]{time, memory1, memory2};
        }
    }
    
    ############
    
    class Solution {
        public int[] memLeak(int memory1, int memory2) {
            int i = 1;
            for (; i <= Math.max(memory1, memory2); ++i) {
                if (memory1 >= memory2) {
                    memory1 -= i;
                } else {
                    memory2 -= i;
                }
            }
            return new int[] {i, memory1, memory2};
        }
    }
    
  • // OJ: https://leetcode.com/problems/incremental-memory-leak/
    // Time: O(sqrt(A + B))
    // Space: O(1)
    class Solution {
    public:
        vector<int> memLeak(int A, int B) {
            int i = 1;
            while (A >= i || B >= i) {
                if (A >= B) {
                    A -= i;
                } else {
                    B -= i;
                }
                ++i;
            }
            return {i, A, B};
        }
    };
    
  • class Solution:
        def memLeak(self, memory1: int, memory2: int) -> List[int]:
            i = 1
            while i <= max(memory1, memory2):
                if memory1 >= memory2:
                    memory1 -= i
                else:
                    memory2 -= i
                i += 1
            return [i, memory1, memory2]
    
    ############
    
    # 1860. Incremental Memory Leak
    # https://leetcode.com/problems/incremental-memory-leak/
    
    class Solution:
        def memLeak(self, m1: int, m2: int) -> List[int]:
            t = 1
            
            while m1 > 0 or m2 > 0:
                if m1 >= m2:
                    if m1 >= t:
                        m1 -= t
                    else:
                        break
                else:
                    if m2 >= t:
                        m2 -= t
                    else:
                        break
                        
                t += 1
            
            return [t, m1, m2]
                
    
    
  • func memLeak(memory1 int, memory2 int) []int {
    	i := 1
    	for ; i <= memory1 || i <= memory2; i++ {
    		if memory1 >= memory2 {
    			memory1 -= i
    		} else {
    			memory2 -= i
    		}
    	}
    	return []int{i, memory1, memory2}
    }
    
  • function memLeak(memory1: number, memory2: number): number[] {
        let i = 1;
        for (; i <= Math.max(memory1, memory2); ++i) {
            if (memory1 >= memory2) {
                memory1 -= i;
            } else {
                memory2 -= i;
            }
        }
        return [i, memory1, memory2];
    }
    
    
  • /**
     * @param {number} memory1
     * @param {number} memory2
     * @return {number[]}
     */
    var memLeak = function (memory1, memory2) {
        let i = 1;
        for (; i <= Math.max(memory1, memory2); ++i) {
            if (memory1 >= memory2) {
                memory1 -= i;
            } else {
                memory2 -= i;
            }
        }
        return [i, memory1, memory2];
    };
    
    

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