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Formatted question description: https://leetcode.ca/all/1789.html
1789. Primary Department for Each Employee
Level
Easy
Description
Table: Employee
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| employee_id | int |
| department_id | int |
| primary_flag | varchar |
+---------------+---------+
(employee_id, department_id) is the primary key for this table.
employee_id is the id of the employee.
department_id is the id of the department to which the employee belongs.
primary_flag is an ENUM of type ('Y', 'N'). If the flag is 'Y', the department is the primary department for the employee. If the flag is 'N', the department is not the primary.
Employees can belong to multiple departments. When the employee joins other departments, they need to decide which department is their primary department. Note that when an employee belongs to only one department, their primary column is 'N'.
Write an SQL query to report all the employees with their primary department. For employees who belong to one department, report their only department.
Return the result table in any order.
The query result format is in the following example.
Employee table:
+-------------+---------------+--------------+
| employee_id | department_id | primary_flag |
+-------------+---------------+--------------+
| 1 | 1 | N |
| 2 | 1 | Y |
| 2 | 2 | N |
| 3 | 3 | N |
| 4 | 2 | N |
| 4 | 3 | Y |
| 4 | 4 | N |
+-------------+---------------+--------------+
Result table:
+-------------+---------------+
| employee_id | department_id |
+-------------+---------------+
| 1 | 1 |
| 2 | 1 |
| 3 | 3 |
| 4 | 3 |
+-------------+---------------+
- The Primary department for employee 1 is 1.
- The Primary department for employee 2 is 1.
- The Primary department for employee 3 is 3.
- The Primary department for employee 4 is 3.
Solution
Select the entries from Employee using primary_flag = 'Y' and select the entries from Employee using count(department_id) = 1. Use union to union the entries into the result.
# Write your MySQL query statement below
select employee_id, department_id from Employee where primary_flag = 'Y'
union
select employee_id, department_id from Employee
group by employee_id
having count(department_id) = 1;