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1987. Number of Unique Good Subsequences

Description

You are given a binary string binary. A subsequence of binary is considered good if it is not empty and has no leading zeros (with the exception of "0").

Find the number of unique good subsequences of binary.

  • For example, if binary = "001", then all the good subsequences are ["0", "0", "1"], so the unique good subsequences are "0" and "1". Note that subsequences "00", "01", and "001" are not good because they have leading zeros.

Return the number of unique good subsequences of binary. Since the answer may be very large, return it modulo 109 + 7.

A subsequence is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements.

 

Example 1:

Input: binary = "001"
Output: 2
Explanation: The good subsequences of binary are ["0", "0", "1"].
The unique good subsequences are "0" and "1".

Example 2:

Input: binary = "11"
Output: 2
Explanation: The good subsequences of binary are ["1", "1", "11"].
The unique good subsequences are "1" and "11".

Example 3:

Input: binary = "101"
Output: 5
Explanation: The good subsequences of binary are ["1", "0", "1", "10", "11", "101"]. 
The unique good subsequences are "0", "1", "10", "11", and "101".

 

Constraints:

  • 1 <= binary.length <= 105
  • binary consists of only '0's and '1's.

Solutions

  • class Solution {
        public int numberOfUniqueGoodSubsequences(String binary) {
            final int mod = (int) 1e9 + 7;
            int f = 0, g = 0;
            int ans = 0;
            for (int i = 0; i < binary.length(); ++i) {
                if (binary.charAt(i) == '0') {
                    g = (g + f) % mod;
                    ans = 1;
                } else {
                    f = (f + g + 1) % mod;
                }
            }
            ans = (ans + f + g) % mod;
            return ans;
        }
    }
    
  • class Solution {
    public:
        int numberOfUniqueGoodSubsequences(string binary) {
            const int mod = 1e9 + 7;
            int f = 0, g = 0;
            int ans = 0;
            for (char& c : binary) {
                if (c == '0') {
                    g = (g + f) % mod;
                    ans = 1;
                } else {
                    f = (f + g + 1) % mod;
                }
            }
            ans = (ans + f + g) % mod;
            return ans;
        }
    };
    
  • class Solution:
        def numberOfUniqueGoodSubsequences(self, binary: str) -> int:
            f = g = 0
            ans = 0
            mod = 10**9 + 7
            for c in binary:
                if c == "0":
                    g = (g + f) % mod
                    ans = 1
                else:
                    f = (f + g + 1) % mod
            ans = (ans + f + g) % mod
            return ans
    
    
  • func numberOfUniqueGoodSubsequences(binary string) (ans int) {
    	const mod int = 1e9 + 7
    	f, g := 0, 0
    	for _, c := range binary {
    		if c == '0' {
    			g = (g + f) % mod
    			ans = 1
    		} else {
    			f = (f + g + 1) % mod
    		}
    	}
    	ans = (ans + f + g) % mod
    	return
    }
    
  • function numberOfUniqueGoodSubsequences(binary: string): number {
        let [f, g] = [0, 0];
        let ans = 0;
        const mod = 1e9 + 7;
        for (const c of binary) {
            if (c === '0') {
                g = (g + f) % mod;
                ans = 1;
            } else {
                f = (f + g + 1) % mod;
            }
        }
        ans = (ans + f + g) % mod;
        return ans;
    }
    
    

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