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1954. Minimum Garden Perimeter to Collect Enough Apples

Description

In a garden represented as an infinite 2D grid, there is an apple tree planted at every integer coordinate. The apple tree planted at an integer coordinate (i, j) has |i| + |j| apples growing on it.

You will buy an axis-aligned square plot of land that is centered at (0, 0).

Given an integer neededApples, return the minimum perimeter of a plot such that at least neededApples apples are inside or on the perimeter of that plot.

The value of |x| is defined as:

  • x if x >= 0
  • -x if x < 0

 

Example 1:

Input: neededApples = 1
Output: 8
Explanation: A square plot of side length 1 does not contain any apples.
However, a square plot of side length 2 has 12 apples inside (as depicted in the image above).
The perimeter is 2 * 4 = 8.

Example 2:

Input: neededApples = 13
Output: 16

Example 3:

Input: neededApples = 1000000000
Output: 5040

 

Constraints:

  • 1 <= neededApples <= 1015

Solutions

  • class Solution {
        public long minimumPerimeter(long neededApples) {
            long x = 1;
            while (2 * x * (x + 1) * (2 * x + 1) < neededApples) {
                ++x;
            }
            return 8 * x;
        }
    }
    
  • class Solution {
    public:
        long long minimumPerimeter(long long neededApples) {
            long long x = 1;
            while (2 * x * (x + 1) * (2 * x + 1) < neededApples) {
                ++x;
            }
            return 8 * x;
        }
    };
    
  • class Solution:
        def minimumPerimeter(self, neededApples: int) -> int:
            x = 1
            while 2 * x * (x + 1) * (2 * x + 1) < neededApples:
                x += 1
            return x * 8
    
    
  • func minimumPerimeter(neededApples int64) int64 {
    	var x int64 = 1
    	for 2*x*(x+1)*(2*x+1) < neededApples {
    		x++
    	}
    	return 8 * x
    }
    
  • function minimumPerimeter(neededApples: number): number {
        let x = 1;
        while (2 * x * (x + 1) * (2 * x + 1) < neededApples) {
            ++x;
        }
        return 8 * x;
    }
    
    

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