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1716. Calculate Money in Leetcode Bank
Description
Hercy wants to save money for his first car. He puts money in the Leetcode bank every day.
He starts by putting in $1 on Monday, the first day. Every day from Tuesday to Sunday, he will put in $1 more than the day before. On every subsequent Monday, he will put in $1 more than the previous Monday.
Given n, return the total amount of money he will have in the Leetcode bank at the end of the nth day.
Example 1:
Input: n = 4 Output: 10 Explanation: After the 4th day, the total is 1 + 2 + 3 + 4 = 10.
Example 2:
Input: n = 10 Output: 37 Explanation: After the 10th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4) = 37. Notice that on the 2nd Monday, Hercy only puts in $2.
Example 3:
Input: n = 20 Output: 96 Explanation: After the 20th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4 + 5 + 6 + 7 + 8) + (3 + 4 + 5 + 6 + 7 + 8) = 96.
Constraints:
1 <= n <= 1000
Solutions
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class Solution { public int totalMoney(int n) { int a = n / 7, b = n % 7; return (28 + 28 + 7 * (a - 1)) * a / 2 + (a * 2 + b + 1) * b / 2; } } -
class Solution { public: int totalMoney(int n) { int a = n / 7, b = n % 7; return (28 + 28 + 7 * (a - 1)) * a / 2 + (a * 2 + b + 1) * b / 2; } }; -
class Solution: def totalMoney(self, n: int) -> int: a, b = divmod(n, 7) return (28 + 28 + 7 * (a - 1)) * a // 2 + (a * 2 + b + 1) * b // 2 -
func totalMoney(n int) int { a, b := n/7, n%7 return (28+28+7*(a-1))*a/2 + (a*2+b+1)*b/2 }