Formatted question description: https://leetcode.ca/all/1668.html

# 1668. Maximum Repeating Substring (Easy)

For a string sequence, a string word is k-repeating if word concatenated k times is a substring of sequence. The word's maximum k-repeating value is the highest value k where word is k-repeating in sequence. If word is not a substring of sequence, word's maximum k-repeating value is 0.

Given strings sequence and word, return the maximum k-repeating value of word in sequence.

Example 1:

Input: sequence = "ababc", word = "ab"
Output: 2
Explanation: "abab" is a substring in "ababc".


Example 2:

Input: sequence = "ababc", word = "ba"
Output: 1
Explanation: "ba" is a substring in "ababc". "baba" is not a substring in "ababc".


Example 3:

Input: sequence = "ababc", word = "ac"
Output: 0
Explanation: "ac" is not a substring in "ababc".


Constraints:

• 1 <= sequence.length <= 100
• 1 <= word.length <= 100
• sequence and word contains only lowercase English letters.

Related Topics:
String

Similar Questions:

## Solution 1. Brute force

Note that find takes O(N^2) instead of O(N).

// OJ: https://leetcode.com/problems/maximum-repeating-substring/

// Time: O(N^3)
// Space: O(N)
class Solution {
public:
int maxRepeating(string sequence, string word) {
string f = word;
int k = 1;
for (; sequence.find(f) != string::npos; ++k, f += word);
return k - 1;
}
};


Java

class Solution {
public int maxRepeating(String sequence, String word) {
int maxRepeating = 0;
StringBuffer sb = new StringBuffer();
int k = 0;
while (sb.length() <= sequence.length()) {
sb.append(word);
k++;
if (sequence.indexOf(sb.toString()) >= 0)
maxRepeating = k;
}
return maxRepeating;
}
}