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Formatted question description: https://leetcode.ca/all/1528.html

# 1528. Shuffle String

Easy

## Description

Given a string s and an integer array indices of the same length.

The string s will be shuffled such that the character at the i-th position moves to indices[i] in the shuffled string.

Return the shuffled string.

Example 1:

Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]

Output: “leetcode”

Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.

Example 2:

Input: s = “abc”, indices = [0,1,2]

Output: “abc”

Explanation: After shuffling, each character remains in its position.

Example 3:

Input: s = “aiohn”, indices = [3,1,4,2,0]

Output: “nihao”

Example 4:

Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]

Output: “arigatou”

Example 5:

Input: s = “art”, indices = [1,0,2]

Output: “rat”

Constraints:

• s.length == indices.length == n
• 1 <= n <= 100
• s contains only lower-case English letters.
• 0 <= indices[i] < n
• All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n - 1).

## Solution

Create an array array of type char with length n. For each i from 0 to n - 1, set array[indices[i]] = s.charAt(i). Finally, convert array to a string and return.

• class Solution {
public String restoreString(String s, int[] indices) {
int length = indices.length;
char[] array = new char[length];
for (int i = 0; i < length; i++) {
char c = s.charAt(i);
int index = indices[i];
array[index] = c;
}
return new String(array);
}
}

############

class Solution {
public String restoreString(String s, int[] indices) {
int n = s.length();
char[] ans = new char[n];
for (int i = 0; i < n; ++i) {
ans[indices[i]] = s.charAt(i);
}
return String.valueOf(ans);
}
}

• class Solution:
def restoreString(self, s: str, indices: List[int]) -> str:
ans = [0] * len(s)
for i, c in enumerate(s):
ans[indices[i]] = c
return ''.join(ans)


• class Solution {
public:
string restoreString(string s, vector<int>& indices) {
int n = s.size();
string ans(n, 0);
for (int i = 0; i < n; ++i) {
ans[indices[i]] = s[i];
}
return ans;
}
};

• func restoreString(s string, indices []int) string {
ans := make([]rune, len(s))
for i, c := range s {
ans[indices[i]] = c
}
return string(ans)
}

• /**
* @param {string} s
* @param {number[]} indices
* @return {string}
*/
var restoreString = function (s, indices) {
let rs = [];
for (let i = 0; i < s.length; i++) {
rs[indices[i]] = s[i];
}
return rs.join("");
};