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Formatted question description: https://leetcode.ca/all/1528.html
1528. Shuffle String
Level
Easy
Description
Given a string s
and an integer array indices
of the same length.
The string s
will be shuffled such that the character at the ith
position moves to indices[i]
in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]
Output: “leetcode”
Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.
Example 2:
Input: s = “abc”, indices = [0,1,2]
Output: “abc”
Explanation: After shuffling, each character remains in its position.
Example 3:
Input: s = “aiohn”, indices = [3,1,4,2,0]
Output: “nihao”
Example 4:
Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]
Output: “arigatou”
Example 5:
Input: s = “art”, indices = [1,0,2]
Output: “rat”
Constraints:
s.length == indices.length == n
1 <= n <= 100
s
contains only lowercase English letters.0 <= indices[i] < n
 All values of
indices
are unique (i.e.indices
is a permutation of the integers from0
ton  1
).
Solution
Create an array array
of type char
with length n
. For each i
from 0 to n  1
, set array[indices[i]] = s.charAt(i)
. Finally, convert array
to a string and return.

class Solution { public String restoreString(String s, int[] indices) { int length = indices.length; char[] array = new char[length]; for (int i = 0; i < length; i++) { char c = s.charAt(i); int index = indices[i]; array[index] = c; } return new String(array); } }

Todo

class Solution: def restoreString(self, s: str, indices: List[int]) > str: ans = [0] * len(s) for i, c in enumerate(s): ans[indices[i]] = c return ''.join(ans)