Formatted question description: https://leetcode.ca/all/1528.html
1528. Shuffle String
Level
Easy
Description
Given a string s and an integer array indices of the same length.
The string s will be shuffled such that the character at the i-th position moves to indices[i] in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]
Output: “leetcode”
Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.
Example 2:
Input: s = “abc”, indices = [0,1,2]
Output: “abc”
Explanation: After shuffling, each character remains in its position.
Example 3:
Input: s = “aiohn”, indices = [3,1,4,2,0]
Output: “nihao”
Example 4:
Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]
Output: “arigatou”
Example 5:
Input: s = “art”, indices = [1,0,2]
Output: “rat”
Constraints:
s.length == indices.length == n1 <= n <= 100scontains only lower-case English letters.0 <= indices[i] < n- All values of
indicesare unique (i.e.indicesis a permutation of the integers from0ton - 1).
Solution
Create an array array of type char with length n. For each i from 0 to n - 1, set array[indices[i]] = s.charAt(i). Finally, convert array to a string and return.
class Solution {
public String restoreString(String s, int[] indices) {
int length = indices.length;
char[] array = new char[length];
for (int i = 0; i < length; i++) {
char c = s.charAt(i);
int index = indices[i];
array[index] = c;
}
return new String(array);
}
}