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Formatted question description: https://leetcode.ca/all/1528.html

1528. Shuffle String

Level

Easy

Description

Given a string s and an integer array indices of the same length.

The string s will be shuffled such that the character at the i-th position moves to indices[i] in the shuffled string.

Return the shuffled string.

Example 1:

Image text

Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]

Output: “leetcode”

Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.

Example 2:

Input: s = “abc”, indices = [0,1,2]

Output: “abc”

Explanation: After shuffling, each character remains in its position.

Example 3:

Input: s = “aiohn”, indices = [3,1,4,2,0]

Output: “nihao”

Example 4:

Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]

Output: “arigatou”

Example 5:

Input: s = “art”, indices = [1,0,2]

Output: “rat”

Constraints:

  • s.length == indices.length == n
  • 1 <= n <= 100
  • s contains only lower-case English letters.
  • 0 <= indices[i] < n
  • All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n - 1).

Solution

Create an array array of type char with length n. For each i from 0 to n - 1, set array[indices[i]] = s.charAt(i). Finally, convert array to a string and return.

  • class Solution {
    public String restoreString(String s, int[] indices) {
        int length = indices.length;
        char[] array = new char[length];
        for (int i = 0; i < length; i++) {
            char c = s.charAt(i);
            int index = indices[i];
            array[index] = c;
        }
        return new String(array);
    }
}

  • Todo

  • class Solution:
    def restoreString(self, s: str, indices: List[int]) -> str:
        ans = [0] * len(s)
        for i, c in enumerate(s):
            ans[indices[i]] = c
        return ''.join(ans)

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