Welcome to Subscribe On Youtube

1528. Shuffle String

Description

You are given a string s and an integer array indices of the same length. The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string.

Return the shuffled string.

 

Example 1:

Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.

Example 2:

Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.

 

Constraints:

• s.length == indices.length == n
• 1 <= n <= 100
• s consists of only lowercase English letters.
• 0 <= indices[i] < n
• All values of indices are unique.

Solutions

• Java
• C++
• Python
• Go
• Javascript
• TypeScript
• RenderScript

• class Solution {
      public String restoreString(String s, int[] indices) {
          int n = s.length();
          char[] ans = new char[n];
          for (int i = 0; i < n; ++i) {
              ans[indices[i]] = s.charAt(i);
          }
          return String.valueOf(ans);
      }
  }
  

• class Solution {
  public:
      string restoreString(string s, vector<int>& indices) {
          int n = s.size();
          string ans(n, 0);
          for (int i = 0; i < n; ++i) {
              ans[indices[i]] = s[i];
          }
          return ans;
      }
  };
  

• class Solution:
      def restoreString(self, s: str, indices: List[int]) -> str:
          ans = [0] * len(s)
          for i, c in enumerate(s):
              ans[indices[i]] = c
          return ''.join(ans)
  
  

• func restoreString(s string, indices []int) string {
  	ans := make([]rune, len(s))
  	for i, c := range s {
  		ans[indices[i]] = c
  	}
  	return string(ans)
  }
  

• /**
   * @param {string} s
   * @param {number[]} indices
   * @return {string}
   */
  var restoreString = function (s, indices) {
      let rs = [];
      for (let i = 0; i < s.length; i++) {
          rs[indices[i]] = s[i];
      }
      return rs.join('');
  };
  
  

• function restoreString(s: string, indices: number[]): string {
      const ans: string[] = [];
      for (let i = 0; i < s.length; i++) {
          ans[indices[i]] = s[i];
      }
      return ans.join('');
  }
  
  

• impl Solution {
      pub fn restore_string(s: String, indices: Vec<i32>) -> String {
          let n = s.len();
          let mut ans = vec![' '; n];
          let chars: Vec<char> = s.chars().collect();
          for i in 0..n {
              ans[indices[i] as usize] = chars[i];
          }
          ans.iter().collect()
      }
  }
  
  

All Problems

All Solutions