Welcome to Subscribe On Youtube

1429. First Unique Number

Description

You have a queue of integers, you need to retrieve the first unique integer in the queue.

Implement the FirstUnique class:

  • FirstUnique(int[] nums) Initializes the object with the numbers in the queue.
  • int showFirstUnique() returns the value of the first unique integer of the queue, and returns -1 if there is no such integer.
  • void add(int value) insert value to the queue.

 

Example 1:

Input: 
["FirstUnique","showFirstUnique","add","showFirstUnique","add","showFirstUnique","add","showFirstUnique"]
[[[2,3,5]],[],[5],[],[2],[],[3],[]]
Output: 
[null,2,null,2,null,3,null,-1]
Explanation: 
FirstUnique firstUnique = new FirstUnique([2,3,5]);
firstUnique.showFirstUnique(); // return 2
firstUnique.add(5);            // the queue is now [2,3,5,5]
firstUnique.showFirstUnique(); // return 2
firstUnique.add(2);            // the queue is now [2,3,5,5,2]
firstUnique.showFirstUnique(); // return 3
firstUnique.add(3);            // the queue is now [2,3,5,5,2,3]
firstUnique.showFirstUnique(); // return -1

Example 2:

Input: 
["FirstUnique","showFirstUnique","add","add","add","add","add","showFirstUnique"]
[[[7,7,7,7,7,7]],[],[7],[3],[3],[7],[17],[]]
Output: 
[null,-1,null,null,null,null,null,17]
Explanation: 
FirstUnique firstUnique = new FirstUnique([7,7,7,7,7,7]);
firstUnique.showFirstUnique(); // return -1
firstUnique.add(7);            // the queue is now [7,7,7,7,7,7,7]
firstUnique.add(3);            // the queue is now [7,7,7,7,7,7,7,3]
firstUnique.add(3);            // the queue is now [7,7,7,7,7,7,7,3,3]
firstUnique.add(7);            // the queue is now [7,7,7,7,7,7,7,3,3,7]
firstUnique.add(17);           // the queue is now [7,7,7,7,7,7,7,3,3,7,17]
firstUnique.showFirstUnique(); // return 17

Example 3:

Input: 
["FirstUnique","showFirstUnique","add","showFirstUnique"]
[[[809]],[],[809],[]]
Output: 
[null,809,null,-1]
Explanation: 
FirstUnique firstUnique = new FirstUnique([809]);
firstUnique.showFirstUnique(); // return 809
firstUnique.add(809);          // the queue is now [809,809]
firstUnique.showFirstUnique(); // return -1

 

Constraints:

  • 1 <= nums.length <= 10^5
  • 1 <= nums[i] <= 10^8
  • 1 <= value <= 10^8
  • At most 50000 calls will be made to showFirstUnique and add.

Solutions

  • class FirstUnique {
        private Map<Integer, Integer> cnt = new HashMap<>();
        private Set<Integer> unique = new LinkedHashSet<>();
    
        public FirstUnique(int[] nums) {
            for (int v : nums) {
                cnt.put(v, cnt.getOrDefault(v, 0) + 1);
            }
            for (int v : nums) {
                if (cnt.get(v) == 1) {
                    unique.add(v);
                }
            }
        }
    
        public int showFirstUnique() {
            return unique.isEmpty() ? -1 : unique.iterator().next();
        }
    
        public void add(int value) {
            cnt.put(value, cnt.getOrDefault(value, 0) + 1);
            if (cnt.get(value) == 1) {
                unique.add(value);
            } else {
                unique.remove(value);
            }
        }
    }
    
    /**
     * Your FirstUnique object will be instantiated and called as such:
     * FirstUnique obj = new FirstUnique(nums);
     * int param_1 = obj.showFirstUnique();
     * obj.add(value);
     */
    
  • class FirstUnique {
    public:
        FirstUnique(vector<int>& nums) {
            for (int& v : nums) {
                ++cnt[v];
                q.push_back(v);
            }
        }
    
        int showFirstUnique() {
            while (q.size() && cnt[q.front()] != 1) q.pop_front();
            return q.size() ? q.front() : -1;
        }
    
        void add(int value) {
            ++cnt[value];
            q.push_back(value);
        }
    
    private:
        unordered_map<int, int> cnt;
        deque<int> q;
    };
    
    /**
     * Your FirstUnique object will be instantiated and called as such:
     * FirstUnique* obj = new FirstUnique(nums);
     * int param_1 = obj->showFirstUnique();
     * obj->add(value);
     */
    
  • class FirstUnique:
        def __init__(self, nums: List[int]):
            self.cnt = Counter(nums)
            self.unique = OrderedDict({v: 1 for v in nums if self.cnt[v] == 1})
    
        def showFirstUnique(self) -> int:
            return -1 if not self.unique else next(v for v in self.unique.keys())
    
        def add(self, value: int) -> None:
            self.cnt[value] += 1
            if self.cnt[value] == 1:
                self.unique[value] = 1
            elif value in self.unique:
                self.unique.pop(value)
    
    
    # Your FirstUnique object will be instantiated and called as such:
    # obj = FirstUnique(nums)
    # param_1 = obj.showFirstUnique()
    # obj.add(value)
    
    
  • type FirstUnique struct {
    	cnt map[int]int
    	q   []int
    }
    
    func Constructor(nums []int) FirstUnique {
    	cnt := map[int]int{}
    	for _, v := range nums {
    		cnt[v]++
    	}
    	return FirstUnique{cnt, nums}
    }
    
    func (this *FirstUnique) ShowFirstUnique() int {
    	for len(this.q) > 0 && this.cnt[this.q[0]] != 1 {
    		this.q = this.q[1:]
    	}
    	if len(this.q) > 0 {
    		return this.q[0]
    	}
    	return -1
    }
    
    func (this *FirstUnique) Add(value int) {
    	this.cnt[value]++
    	this.q = append(this.q, value)
    }
    
    /**
     * Your FirstUnique object will be instantiated and called as such:
     * obj := Constructor(nums);
     * param_1 := obj.ShowFirstUnique();
     * obj.Add(value);
     */
    

All Problems

All Solutions