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1407. Top Travellers
Description
Table: Users
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | name | varchar | +---------------+---------+ id is the column with unique values for this table. name is the name of the user.
Table: Rides
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | user_id | int | | distance | int | +---------------+---------+ id is the column with unique values for this table. user_id is the id of the user who traveled the distance "distance".
Write a solution to report the distance traveled by each user.
Return the result table ordered by travelled_distance
in descending order, if two or more users traveled the same distance, order them by their name
in ascending order.
The result format is in the following example.
Example 1:
Input: Users table: +------+-----------+ | id | name | +------+-----------+ | 1 | Alice | | 2 | Bob | | 3 | Alex | | 4 | Donald | | 7 | Lee | | 13 | Jonathan | | 19 | Elvis | +------+-----------+ Rides table: +------+----------+----------+ | id | user_id | distance | +------+----------+----------+ | 1 | 1 | 120 | | 2 | 2 | 317 | | 3 | 3 | 222 | | 4 | 7 | 100 | | 5 | 13 | 312 | | 6 | 19 | 50 | | 7 | 7 | 120 | | 8 | 19 | 400 | | 9 | 7 | 230 | +------+----------+----------+ Output: +----------+--------------------+ | name | travelled_distance | +----------+--------------------+ | Elvis | 450 | | Lee | 450 | | Bob | 317 | | Jonathan | 312 | | Alex | 222 | | Alice | 120 | | Donald | 0 | +----------+--------------------+ Explanation: Elvis and Lee traveled 450 miles, Elvis is the top traveler as his name is alphabetically smaller than Lee. Bob, Jonathan, Alex, and Alice have only one ride and we just order them by the total distances of the ride. Donald did not have any rides, the distance traveled by him is 0.
Solutions
Solution 1: LEFT JOIN + GROUP BY
We can use a left join to join the Users
table with the Rides
table on the condition of user id, and then group by user id to calculate the travel distance for each user. Note that if a user has no travel records, the travel distance is $0$.
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# Write your MySQL query statement below SELECT a.name, IFNULL(SUM(b.distance), 0) AS travelled_distance FROM Users AS a LEFT JOIN Rides AS b ON a.id = b.user_id GROUP BY a.name ORDER BY travelled_distance DESC, name ASC; -- SELECT name, IFNULL(SUM(distance), 0) AS travelled_distance FROM Users AS u LEFT JOIN Rides AS r ON u.id = r.user_id GROUP BY u.id ORDER BY 2 DESC, 1;