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Formatted question description: https://leetcode.ca/all/1389.html

1389. Create Target Array in the Given Order (Easy)

Given two arrays of integers nums and index. Your task is to create target array under the following rules:

  • Initially target array is empty.
  • From left to right read nums[i] and index[i], insert at index index[i] the value nums[i] in target array.
  • Repeat the previous step until there are no elements to read in nums and index.

Return the target array.

It is guaranteed that the insertion operations will be valid.

 

Example 1:

Input: nums = [0,1,2,3,4], index = [0,1,2,2,1]
Output: [0,4,1,3,2]
Explanation:
nums       index     target
0            0        [0]
1            1        [0,1]
2            2        [0,1,2]
3            2        [0,1,3,2]
4            1        [0,4,1,3,2]

Example 2:

Input: nums = [1,2,3,4,0], index = [0,1,2,3,0]
Output: [0,1,2,3,4]
Explanation:
nums       index     target
1            0        [1]
2            1        [1,2]
3            2        [1,2,3]
4            3        [1,2,3,4]
0            0        [0,1,2,3,4]

Example 3:

Input: nums = [1], index = [0]
Output: [1]

 

Constraints:

  • 1 <= nums.length, index.length <= 100
  • nums.length == index.length
  • 0 <= nums[i] <= 100
  • 0 <= index[i] <= i

Related Topics:
Array

Solution 1.

  • class Solution {
        public int[] createTargetArray(int[] nums, int[] index) {
            List<Integer> list = new ArrayList<Integer>();
            int length = nums.length;
            for (int i = 0; i < length; i++)
                list.add(index[i], nums[i]);
            int[] target = new int[length];
            for (int i = 0; i < length; i++)
                target[i] = list.get(i);
            return target;
        }
    }
    
    ############
    
    class Solution {
        public int[] createTargetArray(int[] nums, int[] index) {
            int n = nums.length;
            List<Integer> target = new ArrayList<>();
            for (int i = 0; i < n; ++i) {
                target.add(index[i], nums[i]);
            }
            int[] res = new int[n];
            for (int i = 0; i < n; ++i) {
                res[i] = target.get(i);
            }
            return res;
        }
    }
    
  • // OJ: https://leetcode.com/problems/create-target-array-in-the-given-order/
    // Time: O(N^2)
    // Space: O(1)
    class Solution {
    public:
        vector<int> createTargetArray(vector<int>& nums, vector<int>& index) {
            vector<int> ans;
            int N = nums.size();
            for (int i = 0; i < N; ++i) {
                ans.insert(ans.begin() + index[i], nums[i]);
            }
            return ans;
        }
    };
    
  • class Solution:
        def createTargetArray(self, nums: List[int], index: List[int]) -> List[int]:
            target = []
            for i in range(len(nums)):
                target.insert(index[i], nums[i])
            return target
    
    
    
  • func createTargetArray(nums []int, index []int) []int {
    	target := make([]int, len(nums))
    	for i, v := range nums {
    		copy(target[index[i]+1:], target[index[i]:])
    		target[index[i]] = v
    	}
    	return target
    }
    
  • function createTargetArray(nums: number[], index: number[]): number[] {
        let ans = [];
        for (let i = 0; i < nums.length; i++) {
            ans.splice(index[i], 0, nums[i]);
        }
        return ans;
    }
    
    

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