Welcome to Subscribe On Youtube
Formatted question description: https://leetcode.ca/all/1344.html
1344. Angle Between Hands of a Clock (Medium)
Given two numbers, hour
and minutes
. Return the smaller angle (in sexagesimal units) formed between the hour
and the minute
hand.
Example 1:
Input: hour = 12, minutes = 30 Output: 165
Example 2:
Input: hour = 3, minutes = 30 Output: 75
Example 3:
Input: hour = 3, minutes = 15 Output: 7.5
Example 4:
Input: hour = 4, minutes = 50 Output: 155
Example 5:
Input: hour = 12, minutes = 0 Output: 0
Constraints:
1 <= hour <= 12
0 <= minutes <= 59
- Answers within
10^-5
of the actual value will be accepted as correct.
Related Topics:
Math
Solution 1.
-
class Solution { public double angleClock(int hour, int minutes) { double hoursDegree = hour * 30 + minutes * 30.0 / 60; int minutesDegree = minutes * 6; double angle = Math.abs(minutesDegree - hoursDegree); if (angle > 180) angle = 360 - angle; return angle; } }
-
// OJ: https://leetcode.com/problems/angle-between-hands-of-a-clock/ // Time: O(1) // Space: O(1) class Solution { public: double angleClock(int h, int m) { double a = h * 30 + m * 0.5, b = m * 6, d = abs(a - b); return min(d, 360 - d); } };