Welcome to Subscribe On Youtube
1344. Angle Between Hands of a Clock
Description
Given two numbers, hour
and minutes
, return the smaller angle (in degrees) formed between the hour
and the minute
hand.
Answers within 10^{5}
of the actual value will be accepted as correct.
Example 1:
Input: hour = 12, minutes = 30 Output: 165
Example 2:
Input: hour = 3, minutes = 30 Output: 75
Example 3:
Input: hour = 3, minutes = 15 Output: 7.5
Constraints:
1 <= hour <= 12
0 <= minutes <= 59
Solutions

class Solution { public double angleClock(int hour, int minutes) { double h = 30 * hour + 0.5 * minutes; double m = 6 * minutes; double diff = Math.abs(h  m); return Math.min(diff, 360  diff); } }

class Solution { public: double angleClock(int hour, int minutes) { double h = 30 * hour + 0.5 * minutes; double m = 6 * minutes; double diff = abs(h  m); return min(diff, 360  diff); } };

class Solution: def angleClock(self, hour: int, minutes: int) > float: h = 30 * hour + 0.5 * minutes m = 6 * minutes diff = abs(h  m) return min(diff, 360  diff)

func angleClock(hour int, minutes int) float64 { h := 30*float64(hour) + 0.5*float64(minutes) m := 6 * float64(minutes) diff := math.Abs(h  m) return math.Min(diff, 360diff) }

function angleClock(hour: number, minutes: number): number { const h = 30 * hour + 0.5 * minutes; const m = 6 * minutes; const diff = Math.abs(h  m); return Math.min(diff, 360  diff); }