# 1344. Angle Between Hands of a Clock

## Description

Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand.

Answers within 10-5 of the actual value will be accepted as correct.

Example 1:

Input: hour = 12, minutes = 30
Output: 165


Example 2:

Input: hour = 3, minutes = 30
Output: 75


Example 3:

Input: hour = 3, minutes = 15
Output: 7.5


Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59

## Solutions

• class Solution {
public double angleClock(int hour, int minutes) {
double h = 30 * hour + 0.5 * minutes;
double m = 6 * minutes;
double diff = Math.abs(h - m);
return Math.min(diff, 360 - diff);
}
}

• class Solution {
public:
double angleClock(int hour, int minutes) {
double h = 30 * hour + 0.5 * minutes;
double m = 6 * minutes;
double diff = abs(h - m);
return min(diff, 360 - diff);
}
};

• class Solution:
def angleClock(self, hour: int, minutes: int) -> float:
h = 30 * hour + 0.5 * minutes
m = 6 * minutes
diff = abs(h - m)
return min(diff, 360 - diff)


• func angleClock(hour int, minutes int) float64 {
h := 30*float64(hour) + 0.5*float64(minutes)
m := 6 * float64(minutes)
diff := math.Abs(h - m)
return math.Min(diff, 360-diff)
}

• function angleClock(hour: number, minutes: number): number {
const h = 30 * hour + 0.5 * minutes;
const m = 6 * minutes;
const diff = Math.abs(h - m);
return Math.min(diff, 360 - diff);
}