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Formatted question description: https://leetcode.ca/all/1344.html

1344. Angle Between Hands of a Clock (Medium)

Given two numbers, hour and minutes. Return the smaller angle (in sexagesimal units) formed between the hour and the minute hand.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

Example 4:

Input: hour = 4, minutes = 50
Output: 155

Example 5:

Input: hour = 12, minutes = 0
Output: 0

 

Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59
• Answers within 10^-5 of the actual value will be accepted as correct.

Related Topics:
Math

Solution 1.

• Java
• C++

• class Solution {
      public double angleClock(int hour, int minutes) {
          double hoursDegree = hour * 30 + minutes * 30.0 / 60;
          int minutesDegree = minutes * 6;
          double angle = Math.abs(minutesDegree - hoursDegree);
          if (angle > 180)
              angle = 360 - angle;
          return angle;
      }
  }
  

• // OJ: https://leetcode.com/problems/angle-between-hands-of-a-clock/
  // Time: O(1)
  // Space: O(1)
  class Solution {
  public:
      double angleClock(int h, int m) {
          double a = h * 30 + m * 0.5, b = m * 6, d = abs(a - b);
          return min(d, 360 - d);
      }
  };
  

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