Welcome to Subscribe On Youtube

1344. Angle Between Hands of a Clock

Description

Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand.

Answers within 10-5 of the actual value will be accepted as correct.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

 

Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public double angleClock(int hour, int minutes) {
          double h = 30 * hour + 0.5 * minutes;
          double m = 6 * minutes;
          double diff = Math.abs(h - m);
          return Math.min(diff, 360 - diff);
      }
  }
  

• class Solution {
  public:
      double angleClock(int hour, int minutes) {
          double h = 30 * hour + 0.5 * minutes;
          double m = 6 * minutes;
          double diff = abs(h - m);
          return min(diff, 360 - diff);
      }
  };
  

• class Solution:
      def angleClock(self, hour: int, minutes: int) -> float:
          h = 30 * hour + 0.5 * minutes
          m = 6 * minutes
          diff = abs(h - m)
          return min(diff, 360 - diff)
  
  

• func angleClock(hour int, minutes int) float64 {
  	h := 30*float64(hour) + 0.5*float64(minutes)
  	m := 6 * float64(minutes)
  	diff := math.Abs(h - m)
  	return math.Min(diff, 360-diff)
  }
  

• function angleClock(hour: number, minutes: number): number {
      const h = 30 * hour + 0.5 * minutes;
      const m = 6 * minutes;
      const diff = Math.abs(h - m);
      return Math.min(diff, 360 - diff);
  }
  
  

All Problems

All Solutions