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1296. Divide Array in Sets of K Consecutive Numbers

Description

Given an array of integers nums and a positive integer k, check whether it is possible to divide this array into sets of k consecutive numbers.

Return true if it is possible. Otherwise, return false.

 

Example 1:

Input: nums = [1,2,3,3,4,4,5,6], k = 4
Output: true
Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6].

Example 2:

Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3
Output: true
Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11].

Example 3:

Input: nums = [1,2,3,4], k = 3
Output: false
Explanation: Each array should be divided in subarrays of size 3.

 

Constraints:

• 1 <= k <= nums.length <= 105
• 1 <= nums[i] <= 109

 

Note: This question is the same as 846: https://leetcode.com/problems/hand-of-straights/

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public boolean isPossibleDivide(int[] nums, int k) {
          Map<Integer, Integer> cnt = new HashMap<>();
          for (int v : nums) {
              cnt.put(v, cnt.getOrDefault(v, 0) + 1);
          }
          Arrays.sort(nums);
          for (int v : nums) {
              if (cnt.containsKey(v)) {
                  for (int x = v; x < v + k; ++x) {
                      if (!cnt.containsKey(x)) {
                          return false;
                      }
                      cnt.put(x, cnt.get(x) - 1);
                      if (cnt.get(x) == 0) {
                          cnt.remove(x);
                      }
                  }
              }
          }
          return true;
      }
  }
  

• class Solution {
  public:
      bool isPossibleDivide(vector<int>& nums, int k) {
          unordered_map<int, int> cnt;
          for (int& v : nums) ++cnt[v];
          sort(nums.begin(), nums.end());
          for (int& v : nums) {
              if (cnt.count(v)) {
                  for (int x = v; x < v + k; ++x) {
                      if (!cnt.count(x)) {
                          return false;
                      }
                      if (--cnt[x] == 0) {
                          cnt.erase(x);
                      }
                  }
              }
          }
          return true;
      }
  };
  

• class Solution:
      def isPossibleDivide(self, nums: List[int], k: int) -> bool:
          cnt = Counter(nums)
          for v in sorted(nums):
              if cnt[v]:
                  for x in range(v, v + k):
                      if cnt[x] == 0:
                          return False
                      cnt[x] -= 1
                      if cnt[x] == 0:
                          cnt.pop(x)
          return True
  
  

• func isPossibleDivide(nums []int, k int) bool {
  	cnt := map[int]int{}
  	for _, v := range nums {
  		cnt[v]++
  	}
  	sort.Ints(nums)
  	for _, v := range nums {
  		if _, ok := cnt[v]; ok {
  			for x := v; x < v+k; x++ {
  				if _, ok := cnt[x]; !ok {
  					return false
  				}
  				cnt[x]--
  				if cnt[x] == 0 {
  					delete(cnt, x)
  				}
  			}
  		}
  	}
  	return true
  }
  

• function isPossibleDivide(nums: number[], k: number): boolean {
      if (nums.length % k !== 0) {
          return false;
      }
      const cnt = new Map<number, number>();
      for (const x of nums) {
          cnt.set(x, (cnt.get(x) || 0) + 1);
      }
      nums.sort((a, b) => a - b);
      for (const x of nums) {
          if (cnt.get(x)! > 0) {
              for (let y = x; y < x + k; y++) {
                  if ((cnt.get(y) || 0) === 0) {
                      return false;
                  }
                  cnt.set(y, cnt.get(y)! - 1);
              }
          }
      }
      return true;
  }
  
  

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