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1270. All People Report to the Given Manager
Description
Table: Employees
+---------------+---------+ | Column Name | Type | +---------------+---------+ | employee_id | int | | employee_name | varchar | | manager_id | int | +---------------+---------+ employee_id is the column of unique values for this table. Each row of this table indicates that the employee with ID employee_id and name employee_name reports his work to his/her direct manager with manager_id The head of the company is the employee with employee_id = 1.
Write a solution to find employee_id
of all employees that directly or indirectly report their work to the head of the company.
The indirect relation between managers will not exceed three managers as the company is small.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input: Employees table: +-------------+---------------+------------+ | employee_id | employee_name | manager_id | +-------------+---------------+------------+ | 1 | Boss | 1 | | 3 | Alice | 3 | | 2 | Bob | 1 | | 4 | Daniel | 2 | | 7 | Luis | 4 | | 8 | Jhon | 3 | | 9 | Angela | 8 | | 77 | Robert | 1 | +-------------+---------------+------------+ Output: +-------------+ | employee_id | +-------------+ | 2 | | 77 | | 4 | | 7 | +-------------+ Explanation: The head of the company is the employee with employee_id 1. The employees with employee_id 2 and 77 report their work directly to the head of the company. The employee with employee_id 4 reports their work indirectly to the head of the company 4 --> 2 --> 1. The employee with employee_id 7 reports their work indirectly to the head of the company 7 --> 4 --> 2 --> 1. The employees with employee_id 3, 8, and 9 do not report their work to the head of the company directly or indirectly.
Solutions
Solution 1: Two Joins
We can use two joins to find all employees who report directly or indirectly to the company CEO.
Specifically, we first use a join to find the manager_id
of the superior manager for each manager_id
, and then use another join to find the manager_id
of the higher-level manager. Finally, if the manager_id
of the higher-level manager is $1$ and the employee_id
of the employee is not $1$, it means that the employee reports directly or indirectly to the company CEO.
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# Write your MySQL query statement below select a.employee_id as EMPLOYEE_ID from Employees as a left join Employees as b on a.manager_id = b.employee_id left join Employees as c on b.manager_id = c.employee_id left join Employees as d on c.manager_id = d.employee_id where a.employee_id != 1 and d.employee_id = 1; -- SELECT e1.employee_id FROM Employees AS e1 JOIN Employees AS e2 ON e1.manager_id = e2.employee_id JOIN Employees AS e3 ON e2.manager_id = e3.employee_id WHERE e1.employee_id != 1 AND e3.manager_id = 1;