Formatted question description: https://leetcode.ca/all/1165.html
1165. Single-Row Keyboard
Level
Easy
Description
There is a special keyboard with all keys in a single row.
Given a string keyboard
of length 26 indicating the layout of the keyboard (indexed from 0 to 25), initially your finger is at index 0. To type a character, you have to move your finger to the index of the desired character. The time taken to move your finger from index i
to index j is |i - j|
.
You want to type a string word
. Write a function to calculate how much time it takes to type it with one finger.
Example 1:
Input: keyboard = “abcdefghijklmnopqrstuvwxyz”, word = “cba”
Output: 4
Explanation: The index moves from 0 to 2 to write ‘c’ then to 1 to write ‘b’ then to 0 again to write ‘a’.
Total time = 2 + 1 + 1 = 4.
Example 2:
Input: keyboard = “pqrstuvwxyzabcdefghijklmno”, word = “leetcode”
Output: 73
Constraints:
keyboard.length == 26
keyboard
contains each English lowercase letter exactly once in some order.1 <= word.length <= 10^4
word[i]
is an English lowercase letter.
Solution
Initially the index is 0. For each letter in word
, find out the index of the letter in keyboard
, calculate the time taken to move the finger, and add the time taken to the total time. Finally, return the total time.
class Solution {
public int calculateTime(String keyboard, String word) {
int time = 0;
int index = 0;
int length = word.length();
for (int i = 0; i < length; i++) {
char c = word.charAt(i);
int curIndex = keyboard.indexOf(c);
time += Math.abs(curIndex - index);
index = curIndex;
}
return time;
}
}