Formatted question description: https://leetcode.ca/all/1132.html

1132. Reported Posts II

Level

Medium

Description

Table: Actions

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| user_id       | int     |
| post_id       | int     |
| action_date   | date    | 
| action        | enum    |
| extra         | varchar |
+---------------+---------+
There is no primary key for this table, it may have duplicate rows.
The action column is an ENUM type of ('view', 'like', 'reaction', 'comment', 'report', 'share').
The extra column has optional information about the action such as a reason for report or a type of reaction. 

Table: Removals

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| post_id       | int     |
| remove_date   | date    | 
+---------------+---------+
post_id is the primary key of this table.
Each row in this table indicates that some post was removed as a result of being reported or as a result of an admin review.

Write an SQL query to find the average for daily percentage of posts that got removed after being reported as spam, rounded to 2 decimal places.

The query result format is in the following example:

Actions table:
+---------+---------+-------------+--------+--------+
| user_id | post_id | action_date | action | extra  |
+---------+---------+-------------+--------+--------+
| 1       | 1       | 2019-07-01  | view   | null   |
| 1       | 1       | 2019-07-01  | like   | null   |
| 1       | 1       | 2019-07-01  | share  | null   |
| 2       | 2       | 2019-07-04  | view   | null   |
| 2       | 2       | 2019-07-04  | report | spam   |
| 3       | 4       | 2019-07-04  | view   | null   |
| 3       | 4       | 2019-07-04  | report | spam   |
| 4       | 3       | 2019-07-02  | view   | null   |
| 4       | 3       | 2019-07-02  | report | spam   |
| 5       | 2       | 2019-07-03  | view   | null   |
| 5       | 2       | 2019-07-03  | report | racism |
| 5       | 5       | 2019-07-03  | view   | null   |
| 5       | 5       | 2019-07-03  | report | racism |
+---------+---------+-------------+--------+--------+

Removals table:
+---------+-------------+
| post_id | remove_date |
+---------+-------------+
| 2       | 2019-07-20  |
| 3       | 2019-07-18  |
+---------+-------------+

Result table:
+-----------------------+
| average_daily_percent |
+-----------------------+
| 75.00                 |
+-----------------------+
The percentage for 2019-07-04 is 50% because only one post of two spam reported posts was removed.
The percentage for 2019-07-02 is 100% because one post was reported as spam and it was removed.
The other days had no spam reports so the average is (50 + 100) / 2 = 75%
Note that the output is only one number and that we do not care about the remove dates.

Solution

To find the average, use ifnull. To round the result to 2 decimal places, use round. Join the tables Actions and Removals. Count the number of posts being reported as spam from table Actions where extra column is 'spam'. Count the number of removed posted from table Removals.

# Write your MySQL query statement below
select ifnull(round(sum(remove_count / spam_count * 100) / count(distinct action_date), 2), 0)
    as average_daily_percent
    from (
        select action_date, count(distinct a.post_id) as spam_count, count(distinct r.post_id) as remove_count
            from Actions a left join Removals r on a.post_id = r.post_id
            where a.extra = 'spam'
            group by a.action_date
    ) as a;

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