# 1119. Remove Vowels from a String

## Description

Given a string s, remove the vowels 'a', 'e', 'i', 'o', and 'u' from it, and return the new string.

Example 1:

Input: s = "leetcodeisacommunityforcoders"
Output: "ltcdscmmntyfrcdrs"


Example 2:

Input: s = "aeiou"
Output: ""


Constraints:

• 1 <= s.length <= 1000
• s consists of only lowercase English letters.

## Solutions

Solution 1: Simulation

We can directly traverse the string according to the requirements of the problem, and append characters that are not vowels to the result string.

The time complexity is $O(n)$, where $n$ is the length of the string. Ignoring the space consumption of the answer, the space complexity is $O(1)$.

• class Solution {
public String removeVowels(String s) {
StringBuilder ans = new StringBuilder();
for (int i = 0; i < s.length(); ++i) {
char c = s.charAt(i);
if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
ans.append(c);
}
}
return ans.toString();
}
}

• class Solution {
public:
string removeVowels(string s) {
string ans;
for (char& c : s) {
if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
ans += c;
}
}
return ans;
}
};

• class Solution:
def removeVowels(self, s: str) -> str:
return "".join(c for c in s if c not in "aeiou")


• func removeVowels(s string) string {
ans := []rune{}
for _, c := range s {
if !(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u') {
ans = append(ans, c)
}
}
return string(ans)
}

• function removeVowels(s: string): string {
return s.replace(/[aeiou]/g, '');
}