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1119. Remove Vowels from a String

Description

Given a string s, remove the vowels 'a', 'e', 'i', 'o', and 'u' from it, and return the new string.

 

Example 1:

Input: s = "leetcodeisacommunityforcoders"
Output: "ltcdscmmntyfrcdrs"

Example 2:

Input: s = "aeiou"
Output: ""

 

Constraints:

• 1 <= s.length <= 1000
• s consists of only lowercase English letters.

Solutions

Solution 1: Simulation

We can directly traverse the string according to the requirements of the problem, and append characters that are not vowels to the result string.

The time complexity is $O(n)$, where $n$ is the length of the string. Ignoring the space consumption of the answer, the space complexity is $O(1)$.

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public String removeVowels(String s) {
          StringBuilder ans = new StringBuilder();
          for (int i = 0; i < s.length(); ++i) {
              char c = s.charAt(i);
              if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
                  ans.append(c);
              }
          }
          return ans.toString();
      }
  }
  

• class Solution {
  public:
      string removeVowels(string s) {
          string ans;
          for (char& c : s) {
              if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
                  ans += c;
              }
          }
          return ans;
      }
  };
  

• class Solution:
      def removeVowels(self, s: str) -> str:
          return "".join(c for c in s if c not in "aeiou")
  
  

• func removeVowels(s string) string {
  	ans := []rune{}
  	for _, c := range s {
  		if !(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u') {
  			ans = append(ans, c)
  		}
  	}
  	return string(ans)
  }
  

• function removeVowels(s: string): string {
      return s.replace(/[aeiou]/g, '');
  }
  
  

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