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1119. Remove Vowels from a String

Description

Given a string s, remove the vowels 'a', 'e', 'i', 'o', and 'u' from it, and return the new string.

 

Example 1:

Input: s = "leetcodeisacommunityforcoders"
Output: "ltcdscmmntyfrcdrs"

Example 2:

Input: s = "aeiou"
Output: ""

 

Constraints:

  • 1 <= s.length <= 1000
  • s consists of only lowercase English letters.

Solutions

Solution 1: Simulation

We can directly traverse the string according to the requirements of the problem, and append characters that are not vowels to the result string.

The time complexity is $O(n)$, where $n$ is the length of the string. Ignoring the space consumption of the answer, the space complexity is $O(1)$.

  • class Solution {
    public String removeVowels(String s) {
        StringBuilder ans = new StringBuilder();
        for (int i = 0; i < s.length(); ++i) {
            char c = s.charAt(i);
            if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
                ans.append(c);
            }
        }
        return ans.toString();
    }
}

  • class Solution {
public:
    string removeVowels(string s) {
        string ans;
        for (char& c : s) {
            if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
                ans += c;
            }
        }
        return ans;
    }
};

  • class Solution:
    def removeVowels(self, s: str) -> str:
        return "".join(c for c in s if c not in "aeiou")


  • func removeVowels(s string) string {
	ans := []rune{}
	for _, c := range s {
		if !(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u') {
			ans = append(ans, c)
		}
	}
	return string(ans)
}

  • function removeVowels(s: string): string {
    return s.replace(/[aeiou]/g, '');
}

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