Question

Formatted question description: https://leetcode.ca/all/1099.html

 Given an array A of integers and integer K,
 return the maximum S such that there exists
    i < j with
    A[i] + A[j] = S and
    S < K.
 If no i, j, exist satisfying this equation, return -1.

 Example 1:

 Input: A = [34,23,1,24,75,33,54,8], K = 60
 Output: 58
 Explanation:
    We can use 34 and 24 to sum 58 which is less than 60.

 Example 2:

 Input: A = [10,20,30], K = 15
 Output: -1
 Explanation:
    In this case it's not possible to get a pair sum less that 15.

 Note:
     1 <= A.length <= 100
     1 <= A[i] <= 1000
     1 <= K <= 2000

Algorithm

(brute force) O(n^2)

Enumerate i and j, and then find the maximum value less than K.

time complexity

Two-level loop traversal, so the time complexity is O(n^2)).

Space complexity

Only a constant number of traversals are needed, so the space complexity is O(1).

Code

Java

import java.util.Arrays;


public class Two_Sum_Less_Than_K {
    class Solution {
        public int twoSumLessThanK(int[] A, int K) {
            int res = -1;
            if(A == null || A.length == 0){
                return res;
            }

            Arrays.sort(A);
            int l = 0;
            int r  = A.length-1;
            while(l<r){
                int sum = A[l] + A[r];
                if(sum < K){
                    res = Math.max(res, sum);
                    l++;
                }else{
                    r--;
                }
            }

            return res;
        }
    }
}

1099 - Two Sum Less Than K

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