Formatted question description: https://leetcode.ca/all/1085.html
1085. Sum of Digits in the Minimum Number
Level
Easy
Description
Given an array A of positive integers, let S be the sum of the digits of the minimal element of A.
Return 0 if S is odd, otherwise return 1.
Example 1:
Input: [34,23,1,24,75,33,54,8]
Output: 0
Explanation:
The minimal element is 1, and the sum of those digits is S = 1 which is odd, so the answer is 0.
Example 2:
Input: [99,77,33,66,55]
Output: 1
Explanation:
The minimal element is 33, and the sum of those digits is S = 3 + 3 = 6 which is even, so the answer is 1.
Note:
1 <= A.length <= 1001 <= A[i].length <= 100
Solution
Loop over the array A to find the minimum number. Then calculate the sum of the digits of the minimum number. Finally check whether the sum is odd or even, and return 0 or 1 respectively.
class Solution {
public int sumOfDigits(int[] A) {
int min = Integer.MAX_VALUE;
for (int num : A)
min = Math.min(min, num);
if (min == 0)
return 1;
int sum = 0;
int temp = min;
while (temp > 0) {
sum += temp % 10;
temp /= 10;
}
return sum % 2 == 0 ? 1 : 0;
}
}