Welcome to Subscribe On Youtube
Formatted question description: https://leetcode.ca/all/1082.html
1082. Sales Analysis I
Level
Easy
Description
Table: Product
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| product_id | int |
| product_name | varchar |
| unit_price | int |
+--------------+---------+
product_id is the primary key of this table.
Table: Sales
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| seller_id | int |
| product_id | int |
| buyer_id | int |
| sale_date | date |
| quantity | int |
| price | int |
+------ ------+---------+
This table has no primary key, it can have repeated rows.
product_id is a foreign key to Product table.
Write an SQL query that reports the best seller by total sales price, If there is a tie, report them all.
The query result format is in the following example:
Product table:
+------------+--------------+------------+
| product_id | product_name | unit_price |
+------------+--------------+------------+
| 1 | S8 | 1000 |
| 2 | G4 | 800 |
| 3 | iPhone | 1400 |
+------------+--------------+------------+
Sales table:
+-----------+------------+----------+------------+----------+-------+
| seller_id | product_id | buyer_id | sale_date | quantity | price |
+-----------+------------+----------+------------+----------+-------+
| 1 | 1 | 1 | 2019-01-21 | 2 | 2000 |
| 1 | 2 | 2 | 2019-02-17 | 1 | 800 |
| 2 | 2 | 3 | 2019-06-02 | 1 | 800 |
| 3 | 3 | 4 | 2019-05-13 | 2 | 2800 |
+-----------+------------+----------+------------+----------+-------+
Result table:
+-------------+
| seller_id |
+-------------+
| 1 |
| 3 |
+-------------+
Both sellers with id 1 and 3 sold products with the most total price of 2800.
Solution
In Sales table, find the seller_id that has the maximum sum of price. Use order by sum(price) desc limit 1 to obtain the maximum price. Use group by seller_id so that the sum is calculated according to each seller_id.
# Write your MySQL query statement below
select seller_id from Sales group by seller_id
having sum(price) = (
select sum(price) from sales group by seller_id order by sum(price) desc limit 1
);