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1072. Flip Columns For Maximum Number of Equal Rows

Description

You are given an m x n binary matrix matrix.

You can choose any number of columns in the matrix and flip every cell in that column (i.e., Change the value of the cell from 0 to 1 or vice versa).

Return the maximum number of rows that have all values equal after some number of flips.

 

Example 1:

Input: matrix = [[0,1],[1,1]]
Output: 1
Explanation: After flipping no values, 1 row has all values equal.

Example 2:

Input: matrix = [[0,1],[1,0]]
Output: 2
Explanation: After flipping values in the first column, both rows have equal values.

Example 3:

Input: matrix = [[0,0,0],[0,0,1],[1,1,0]]
Output: 2
Explanation: After flipping values in the first two columns, the last two rows have equal values.

 

Constraints:

  • m == matrix.length
  • n == matrix[i].length
  • 1 <= m, n <= 300
  • matrix[i][j] is either 0 or 1.

Solutions

  • class Solution {
    public int maxEqualRowsAfterFlips(int[][] matrix) {
        Map<String, Integer> cnt = new HashMap<>();
        int ans = 0, n = matrix[0].length;
        for (var row : matrix) {
            char[] cs = new char[n];
            for (int i = 0; i < n; ++i) {
                cs[i] = (char) (row[0] ^ row[i]);
            }
            ans = Math.max(ans, cnt.merge(String.valueOf(cs), 1, Integer::sum));
        }
        return ans;
    }
}

  • class Solution {
public:
    int maxEqualRowsAfterFlips(vector<vector<int>>& matrix) {
        unordered_map<string, int> cnt;
        int ans = 0;
        for (auto& row : matrix) {
            string s;
            for (int x : row) {
                s.push_back('0' + (row[0] == 0 ? x : x ^ 1));
            }
            ans = max(ans, ++cnt[s]);
        }
        return ans;
    }
};

  • class Solution:
    def maxEqualRowsAfterFlips(self, matrix: List[List[int]]) -> int:
        cnt = Counter()
        for row in matrix:
            t = tuple(row) if row[0] == 0 else tuple(x ^ 1 for x in row)
            cnt[t] += 1
        return max(cnt.values())


  • func maxEqualRowsAfterFlips(matrix [][]int) (ans int) {
	cnt := map[string]int{}
	for _, row := range matrix {
		s := []byte{}
		for _, x := range row {
			if row[0] == 1 {
				x ^= 1
			}
			s = append(s, byte(x)+'0')
		}
		t := string(s)
		cnt[t]++
		ans = max(ans, cnt[t])
	}
	return
}

  • function maxEqualRowsAfterFlips(matrix: number[][]): number {
    const cnt = new Map<string, number>();
    let ans = 0;
    for (const row of matrix) {
        if (row[0] === 1) {
            for (let i = 0; i < row.length; i++) {
                row[i] ^= 1;
            }
        }
        const s = row.join('');
        cnt.set(s, (cnt.get(s) || 0) + 1);
        ans = Math.max(ans, cnt.get(s)!);
    }
    return ans;
}

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