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Formatted question description: https://leetcode.ca/all/1051.html

1051. Height Checker (Easy)

Students are asked to stand in non-decreasing order of heights for an annual photo.

Return the minimum number of students that must move in order for all students to be standing in non-decreasing order of height.

Notice that when a group of students is selected they can reorder in any possible way between themselves and the non selected students remain on their seats.

 

Example 1:

Input: heights = [1,1,4,2,1,3]
Output: 3
Explanation: 
Current array : [1,1,4,2,1,3]
Target array  : [1,1,1,2,3,4]
On index 2 (0-based) we have 4 vs 1 so we have to move this student.
On index 4 (0-based) we have 1 vs 3 so we have to move this student.
On index 5 (0-based) we have 3 vs 4 so we have to move this student.

Example 2:

Input: heights = [5,1,2,3,4]
Output: 5

Example 3:

Input: heights = [1,2,3,4,5]
Output: 0

 

Constraints:

• 1 <= heights.length <= 100
• 1 <= heights[i] <= 100

Related Topics:
Array

Solution 1.

• Java
• C++
• Python
• Go

• class Solution {
      public int heightChecker(int[] heights) {
          int length = heights.length;
          int[] sorted = new int[length];
          System.arraycopy(heights, 0, sorted, 0, length);
          Arrays.sort(sorted);
          int count = 0;
          for (int i = 0; i < length; i++) {
              if (heights[i] != sorted[i])
                  count++;
          }
          return count;
      }
  }
  
  ############
  
  class Solution {
      public int heightChecker(int[] heights) {
          int[] expected = heights.clone();
          Arrays.sort(expected);
          int ans = 0;
          for (int i = 0; i < heights.length; ++i) {
              if (heights[i] != expected[i]) {
                  ++ans;
              }
          }
          return ans;
      }
  }
  

• // OJ: https://leetcode.com/problems/height-checker/
  // Time: O(NlogN)
  // Space: O(N)
  class Solution {
  public:
      int heightChecker(vector<int>& A) {
          auto B = A;
          sort(begin(B), end(B));
          int ans = 0;
          for (int i = 0; i < A.size(); ++i) ans += A[i] != B[i];
          return ans;
      }
  };
  

• class Solution:
      def heightChecker(self, heights: List[int]) -> int:
          expected = sorted(heights)
          return sum(a != b for a, b in zip(heights, expected))
  
  ############
  
  class Solution(object):
      def heightChecker(self, heights):
          """
          :type heights: List[int]
          :rtype: int
          """
          return sum(a != b for a, b in zip(sorted(heights), heights))
  

• func heightChecker(heights []int) int {
  	expected := make([]int, len(heights))
  	copy(expected, heights)
  	sort.Ints(expected)
  	ans := 0
  	for i, v := range heights {
  		if v != expected[i] {
  			ans++
  		}
  	}
  	return ans
  }
  

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