Formatted question description: https://leetcode.ca/all/1011.html

1011. Capacity To Ship Packages Within D Days (Medium)

A conveyor belt has packages that must be shipped from one port to another within D days.

The i-th package on the conveyor belt has a weight of weights[i]. Each day, we load the ship with packages on the conveyor belt (in the order given by weights). We may not load more weight than the maximum weight capacity of the ship.

Return the least weight capacity of the ship that will result in all the packages on the conveyor belt being shipped within D days.

Example 1:

Input: weights = [1,2,3,4,5,6,7,8,9,10], D = 5
Output: 15
Explanation: 
A ship capacity of 15 is the minimum to ship all the packages in 5 days like this:
1st day: 1, 2, 3, 4, 5
2nd day: 6, 7
3rd day: 8
4th day: 9
5th day: 10

Note that the cargo must be shipped in the order given, so using a ship of capacity 14 and splitting the packages into parts like (2, 3, 4, 5), (1, 6, 7), (8), (9), (10) is not allowed.

Example 2:

Input: weights = [3,2,2,4,1,4], D = 3
Output: 6
Explanation: 
A ship capacity of 6 is the minimum to ship all the packages in 3 days like this:
1st day: 3, 2
2nd day: 2, 4
3rd day: 1, 4

Example 3:

Input: weights = [1,2,3,1,1], D = 4
Output: 3
Explanation: 
1st day: 1
2nd day: 2
3rd day: 3
4th day: 1, 1

Note:

1 <= D <= weights.length <= 50000
1 <= weights[i] <= 500

Companies:
Google

Related Topics:
Array, Binary Search

Solution 1.

class Solution {
    public int shipWithinDays(int[] weights, int D) {
        int sum = 0;
        int low = 0;
        for (int weight : weights) {
            sum += weight;
            low = Math.max(low, weight);
        }
        int high = sum;
        while (low < high) {
            int mid = (high - low) / 2 + low;
            int days = daysNeed(weights, mid);
            if (days > D)
                low = mid + 1;
            else
                high = mid;
        }
        return low;
    }

    public int daysNeed(int[] weights, int capacity) {
        int days = 1;
        int currentTotal = 0;
        int length = weights.length;
        for (int i = 0; i < length; i++) {
            int weight = weights[i];
            if (currentTotal + weight <= capacity)
                currentTotal += weight;
            else {
                days++;
                currentTotal = weight;
            }
        }
        return days;
    }
}

############

class Solution {
    public int shipWithinDays(int[] weights, int days) {
        int left = 0, right = 0;
        for (int w : weights) {
            left = Math.max(left, w);
            right += w;
        }
        while (left < right) {
            int mid = (left + right) >> 1;
            if (check(mid, weights, days)) {
                right = mid;
            } else {
                left = mid + 1;
            }
        }
        return left;
    }

    private boolean check(int mx, int[] weights, int days) {
        int ws = 0, cnt = 1;
        for (int w : weights) {
            ws += w;
            if (ws > mx) {
                ws = w;
                ++cnt;
            }
        }
        return cnt <= days;
    }
}

class Solution:
    def shipWithinDays(self, weights: List[int], D: int) -> int:
        def check(capacity):
            cnt, t = 1, 0
            for w in weights:
                if w > capacity:
                    return False
                if t + w <= capacity:
                    t += w
                else:
                    cnt += 1
                    t = w
            return cnt <= D

        left, right = 1, 25000000
        while left < right:
            mid = (left + right) >> 1
            if check(mid):
                right = mid
            else:
                left = mid + 1
        return left

############

# 1011. Capacity To Ship Packages Within D Days
# https://leetcode.com/problems/capacity-to-ship-packages-within-d-days/

class Solution:
    def shipWithinDays(self, weights: List[int], days: int) -> int:
        total = sum(weights)
        
        def good(target):
            mmax = s = 0
            day = 1
            
            for x in weights:
                if s + x > target:
                    s = x
                    day += 1
                else:
                    s += x
                mmax = max(mmax, s)
            
            return day <= days and mmax <= target
        
        left, right = 1, total
        
        while left < right:
            mid = left + (right - left) // 2
            
            if good(mid):
                right = mid
            else:
                left = mid + 1
        
        return left

func shipWithinDays(weights []int, days int) int {
	var left, right int
	for _, w := range weights {
		if left < w {
			left = w
		}
		right += w
	}
	return left + sort.Search(right, func(mx int) bool {
		mx += left
		ws, cnt := 0, 1
		for _, w := range weights {
			ws += w
			if ws > mx {
				ws = w
				cnt++
			}
		}
		return cnt <= days
	})
}

function shipWithinDays(weights: number[], days: number): number {
    let left = 0;
    let right = 0;
    for (const w of weights) {
        left = Math.max(left, w);
        right += w;
    }
    const check = (mx: number) => {
        let ws = 0;
        let cnt = 1;
        for (const w of weights) {
            ws += w;
            if (ws > mx) {
                ws = w;
                ++cnt;
            }
        }
        return cnt <= days;
    };
    while (left < right) {
        const mid = (left + right) >> 1;
        if (check(mid)) {
            right = mid;
        } else {
            left = mid + 1;
        }
    }
    return left;
}

class Solution {
public:
    int shipWithinDays(vector<int>& weights, int days) {
        int left = 0, right = 0;
        for (auto& w : weights) {
            left = max(left, w);
            right += w;
        }
        auto check = [&](int mx) {
            int ws = 0, cnt = 1;
            for (auto& w : weights) {
                ws += w;
                if (ws > mx) {
                    ws = w;
                    ++cnt;
                }
            }
            return cnt <= days;
        };
        while (left < right) {
            int mid = (left + right) >> 1;
            if (check(mid)) {
                right = mid;
            } else {
                left = mid + 1;
            }
        }
        return left;
    }
};

1011 - Capacity To Ship Packages Within D Days

1011. Capacity To Ship Packages Within D Days (Medium)

Solution 1.

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1011. Capacity To Ship Packages Within D Days (Medium)

Solution 1.

All Problems

All Solutions