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895. Maximum Frequency Stack
Description
Design a stack-like data structure to push elements to the stack and pop the most frequent element from the stack.
Implement the FreqStack
class:
FreqStack()
constructs an empty frequency stack.void push(int val)
pushes an integerval
onto the top of the stack.int pop()
removes and returns the most frequent element in the stack.- If there is a tie for the most frequent element, the element closest to the stack's top is removed and returned.
Example 1:
Input ["FreqStack", "push", "push", "push", "push", "push", "push", "pop", "pop", "pop", "pop"] [[], [5], [7], [5], [7], [4], [5], [], [], [], []] Output [null, null, null, null, null, null, null, 5, 7, 5, 4] Explanation FreqStack freqStack = new FreqStack(); freqStack.push(5); // The stack is [5] freqStack.push(7); // The stack is [5,7] freqStack.push(5); // The stack is [5,7,5] freqStack.push(7); // The stack is [5,7,5,7] freqStack.push(4); // The stack is [5,7,5,7,4] freqStack.push(5); // The stack is [5,7,5,7,4,5] freqStack.pop(); // return 5, as 5 is the most frequent. The stack becomes [5,7,5,7,4]. freqStack.pop(); // return 7, as 5 and 7 is the most frequent, but 7 is closest to the top. The stack becomes [5,7,5,4]. freqStack.pop(); // return 5, as 5 is the most frequent. The stack becomes [5,7,4]. freqStack.pop(); // return 4, as 4, 5 and 7 is the most frequent, but 4 is closest to the top. The stack becomes [5,7].
Constraints:
0 <= val <= 109
- At most
2 * 104
calls will be made topush
andpop
. - It is guaranteed that there will be at least one element in the stack before calling
pop
.
Solutions
-
class FreqStack { private Map<Integer, Integer> cnt = new HashMap<>(); private Map<Integer, Deque<Integer>> d = new HashMap<>(); private int mx; public FreqStack() { } public void push(int val) { cnt.put(val, cnt.getOrDefault(val, 0) + 1); int t = cnt.get(val); d.computeIfAbsent(t, k -> new ArrayDeque<>()).push(val); mx = Math.max(mx, t); } public int pop() { int val = d.get(mx).pop(); cnt.put(val, cnt.get(val) - 1); if (d.get(mx).isEmpty()) { --mx; } return val; } } /** * Your FreqStack object will be instantiated and called as such: * FreqStack obj = new FreqStack(); * obj.push(val); * int param_2 = obj.pop(); */
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class FreqStack { public: FreqStack() { } void push(int val) { ++cnt[val]; d[cnt[val]].push(val); mx = max(mx, cnt[val]); } int pop() { int val = d[mx].top(); --cnt[val]; d[mx].pop(); if (d[mx].empty()) --mx; return val; } private: unordered_map<int, int> cnt; unordered_map<int, stack<int>> d; int mx = 0; }; /** * Your FreqStack object will be instantiated and called as such: * FreqStack* obj = new FreqStack(); * obj->push(val); * int param_2 = obj->pop(); */
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class FreqStack: def __init__(self): self.cnt = defaultdict(int) self.d = defaultdict(list) self.mx = 0 def push(self, val: int) -> None: self.cnt[val] += 1 self.d[self.cnt[val]].append(val) self.mx = max(self.mx, self.cnt[val]) def pop(self) -> int: val = self.d[self.mx].pop() self.cnt[val] -= 1 if not self.d[self.mx]: self.mx -= 1 return val # Your FreqStack object will be instantiated and called as such: # obj = FreqStack() # obj.push(val) # param_2 = obj.pop()
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type FreqStack struct { cnt map[int]int d map[int][]int mx int } func Constructor() FreqStack { return FreqStack{map[int]int{}, map[int][]int{}, 0} } func (this *FreqStack) Push(val int) { this.cnt[val]++ this.d[this.cnt[val]] = append(this.d[this.cnt[val]], val) this.mx = max(this.mx, this.cnt[val]) } func (this *FreqStack) Pop() int { val := this.d[this.mx][len(this.d[this.mx])-1] this.d[this.mx] = this.d[this.mx][:len(this.d[this.mx])-1] this.cnt[val]-- if len(this.d[this.mx]) == 0 { this.mx-- } return val } /** * Your FreqStack object will be instantiated and called as such: * obj := Constructor(); * obj.Push(val); * param_2 := obj.Pop(); */