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Formatted question description: https://leetcode.ca/all/876.html
876. Middle of the Linked List (Easy)
Given a non-empty, singly linked list with head node head
, return a middle node of linked list.
If there are two middle nodes, return the second middle node.
Example 1:
Input: [1,2,3,4,5]
Output: Node 3 from this list (Serialization: [3,4,5])
The returned node has value 3. (The judge’s serialization of this node is [3,4,5]).
Note that we returned a ListNode object ans, such that:
ans.val = 3, ans.next.val = 4, ans.next.next.val = 5, and ans.next.next.next = NULL.
Example 2:
Input: [1,2,3,4,5,6]
Output: Node 4 from this list (Serialization: [4,5,6])
Since the list has two middle nodes with values 3 and 4, we return the second one.
Note:
- The number of nodes in the given list will be between
1
and100
.
Solution 1. Two Pointers
// OJ: https://leetcode.com/problems/middle-of-the-linked-list/
// Time: O(N)
// Space: O(1)
class Solution {
public:
ListNode* middleNode(ListNode* head) {
auto slow = head, fast = head;
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
}
return slow;
}
};
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/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode middleNode(ListNode head) { if (head == null || head.next == null) return head; ListNode slow = head, fast = head; while (fast != null && fast.next != null) { slow = slow.next; fast = fast.next.next; } return slow; } } ############ /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode() {} * ListNode(int val) { this.val = val; } * ListNode(int val, ListNode next) { this.val = val; this.next = next; } * } */ class Solution { public ListNode middleNode(ListNode head) { ListNode slow = head, fast = head; while (fast != null && fast.next != null) { slow = slow.next; fast = fast.next.next; } return slow; } }
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// OJ: https://leetcode.com/problems/middle-of-the-linked-list/ // Time: O(N) // Space: O(1) class Solution { public: ListNode* middleNode(ListNode* head) { auto slow = head, fast = head; while (fast && fast->next) { slow = slow->next; fast = fast->next->next; } return slow; } };
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# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def middleNode(self, head: ListNode) -> ListNode: slow = fast = head while fast and fast.next: slow, fast = slow.next, fast.next.next return slow ############ 3 # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def middleNode(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(0) dummy.next = head slow, fast = dummy, dummy while fast and fast.next: slow = slow.next fast = fast.next.next return slow.next if fast else slow
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/** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */ func middleNode(head *ListNode) *ListNode { slow, fast := head, head for fast != nil && fast.Next != nil { slow, fast = slow.Next, fast.Next.Next } return slow }
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/** * Definition for singly-linked list. * class ListNode { * val: number * next: ListNode | null * constructor(val?: number, next?: ListNode | null) { * this.val = (val===undefined ? 0 : val) * this.next = (next===undefined ? null : next) * } * } */ function middleNode(head: ListNode | null): ListNode | null { let fast = head, slow = head; while (fast != null && fast.next != null) { fast = fast.next.next; slow = slow.next; } return slow; }
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/** * Definition for a singly-linked list. * class ListNode { * public $val = 0; * public $next = null; * function __construct($val = 0, $next = null) { * $this->val = $val; * $this->next = $next; * } * } */ class Solution { /** * @param ListNode $head * @return ListNode */ function middleNode($head) { $count = 0; $tmpHead = $head; while ($tmpHead != null) { $tmpHead = $tmpHead->next; $count++; } $len = $count - floor($count / 2); while ($count != $len) { $head = $head->next; $count--; } return $head; } }
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// Definition for singly-linked list. // #[derive(PartialEq, Eq, Clone, Debug)] // pub struct ListNode { // pub val: i32, // pub next: Option<Box<ListNode>> // } // // impl ListNode { // #[inline] // fn new(val: i32) -> Self { // ListNode { // next: None, // val // } // } // } impl Solution { pub fn middle_node(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> { let mut slow = &head; let mut fast = &head; while fast.is_some() && fast.as_ref().unwrap().next.is_some() { slow = &slow.as_ref().unwrap().next; fast = &fast.as_ref().unwrap().next.as_ref().unwrap().next; } slow.clone() } }