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876. Middle of the Linked List
Description
Given the head
of a singly linked list, return the middle node of the linked list.
If there are two middle nodes, return the second middle node.
Example 1:
Input: head = [1,2,3,4,5] Output: [3,4,5] Explanation: The middle node of the list is node 3.
Example 2:
Input: head = [1,2,3,4,5,6] Output: [4,5,6] Explanation: Since the list has two middle nodes with values 3 and 4, we return the second one.
Constraints:
- The number of nodes in the list is in the range
[1, 100]
. 1 <= Node.val <= 100
Solutions
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/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode() {} * ListNode(int val) { this.val = val; } * ListNode(int val, ListNode next) { this.val = val; this.next = next; } * } */ class Solution { public ListNode middleNode(ListNode head) { ListNode slow = head, fast = head; while (fast != null && fast.next != null) { slow = slow.next; fast = fast.next.next; } return slow; } }
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/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode() : val(0), next(nullptr) {} * ListNode(int x) : val(x), next(nullptr) {} * ListNode(int x, ListNode *next) : val(x), next(next) {} * }; */ class Solution { public: ListNode* middleNode(ListNode* head) { ListNode *slow = head, *fast = head; while (fast && fast->next) { slow = slow->next; fast = fast->next->next; } return slow; } };
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# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def middleNode(self, head: ListNode) -> ListNode: slow = fast = head while fast and fast.next: slow, fast = slow.next, fast.next.next return slow
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/** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */ func middleNode(head *ListNode) *ListNode { slow, fast := head, head for fast != nil && fast.Next != nil { slow, fast = slow.Next, fast.Next.Next } return slow }
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/** * Definition for singly-linked list. * class ListNode { * val: number * next: ListNode | null * constructor(val?: number, next?: ListNode | null) { * this.val = (val===undefined ? 0 : val) * this.next = (next===undefined ? null : next) * } * } */ function middleNode(head: ListNode | null): ListNode | null { let fast = head, slow = head; while (fast != null && fast.next != null) { fast = fast.next.next; slow = slow.next; } return slow; }
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/** * Definition for a singly-linked list. * class ListNode { * public $val = 0; * public $next = null; * function __construct($val = 0, $next = null) { * $this->val = $val; * $this->next = $next; * } * } */ class Solution { /** * @param ListNode $head * @return ListNode */ function middleNode($head) { $count = 0; $tmpHead = $head; while ($tmpHead != null) { $tmpHead = $tmpHead->next; $count++; } $len = $count - floor($count / 2); while ($count != $len) { $head = $head->next; $count--; } return $head; } }
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// Definition for singly-linked list. // #[derive(PartialEq, Eq, Clone, Debug)] // pub struct ListNode { // pub val: i32, // pub next: Option<Box<ListNode>> // } // // impl ListNode { // #[inline] // fn new(val: i32) -> Self { // ListNode { // next: None, // val // } // } // } impl Solution { pub fn middle_node(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> { let mut slow = &head; let mut fast = &head; while fast.is_some() && fast.as_ref().unwrap().next.is_some() { slow = &slow.as_ref().unwrap().next; fast = &fast.as_ref().unwrap().next.as_ref().unwrap().next; } slow.clone() } }