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831. Masking Personal Information

Description

You are given a personal information string s, representing either an email address or a phone number. Return the masked personal information using the below rules.

Email address:

An email address is:

• A name consisting of uppercase and lowercase English letters, followed by
• The '@' symbol, followed by
• The domain consisting of uppercase and lowercase English letters with a dot '.' somewhere in the middle (not the first or last character).

To mask an email:

• The uppercase letters in the name and domain must be converted to lowercase letters.
• The middle letters of the name (i.e., all but the first and last letters) must be replaced by 5 asterisks "*****".

Phone number:

A phone number is formatted as follows:

• The phone number contains 10-13 digits.
• The last 10 digits make up the local number.
• The remaining 0-3 digits, in the beginning, make up the country code.
• Separation characters from the set {'+', '-', '(', ')', ' '} separate the above digits in some way.

To mask a phone number:

• Remove all separation characters.
• The masked phone number should have the form:
  • "***-***-XXXX" if the country code has 0 digits.
  • "+*-***-***-XXXX" if the country code has 1 digit.
  • "+**-***-***-XXXX" if the country code has 2 digits.
  • "+***-***-***-XXXX" if the country code has 3 digits.
• "XXXX" is the last 4 digits of the local number.

 

Example 1:

Input: s = "LeetCode@LeetCode.com"
Output: "l*****e@leetcode.com"
Explanation: s is an email address.
The name and domain are converted to lowercase, and the middle of the name is replaced by 5 asterisks.

Example 2:

Input: s = "AB@qq.com"
Output: "a*****b@qq.com"
Explanation: s is an email address.
The name and domain are converted to lowercase, and the middle of the name is replaced by 5 asterisks.
Note that even though "ab" is 2 characters, it still must have 5 asterisks in the middle.

Example 3:

Input: s = "1(234)567-890"
Output: "***-***-7890"
Explanation: s is a phone number.
There are 10 digits, so the local number is 10 digits and the country code is 0 digits.
Thus, the resulting masked number is "***-***-7890".

 

Constraints:

• s is either a valid email or a phone number.
• If s is an email:
  • 8 <= s.length <= 40
  • s consists of uppercase and lowercase English letters and exactly one '@' symbol and '.' symbol.
• If s is a phone number:
  • 10 <= s.length <= 20
  • s consists of digits, spaces, and the symbols '(', ')', '-', and '+'.

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public String maskPII(String s) {
          if (Character.isLetter(s.charAt(0))) {
              s = s.toLowerCase();
              int i = s.indexOf('@');
              return s.substring(0, 1) + "*****" + s.substring(i - 1);
          }
          StringBuilder sb = new StringBuilder();
          for (char c : s.toCharArray()) {
              if (Character.isDigit(c)) {
                  sb.append(c);
              }
          }
          s = sb.toString();
          int cnt = s.length() - 10;
          String suf = "***-***-" + s.substring(s.length() - 4);
          return cnt == 0 ? suf
                          : "+"
                  + "*".repeat(cnt) + "-" + suf;
      }
  }
  

• class Solution {
  public:
      string maskPII(string s) {
          int i = s.find('@');
          if (i != -1) {
              string ans;
              ans += tolower(s[0]);
              ans += "*****";
              for (int j = i - 1; j < s.size(); ++j) {
                  ans += tolower(s[j]);
              }
              return ans;
          }
          string t;
          for (char c : s) {
              if (isdigit(c)) {
                  t += c;
              }
          }
          int cnt = t.size() - 10;
          string suf = "***-***-" + t.substr(t.size() - 4);
          return cnt == 0 ? suf : "+" + string(cnt, '*') + "-" + suf;
      }
  };
  

• class Solution:
      def maskPII(self, s: str) -> str:
          if s[0].isalpha():
              s = s.lower()
              return s[0] + '*****' + s[s.find('@') - 1 :]
          s = ''.join(c for c in s if c.isdigit())
          cnt = len(s) - 10
          suf = '***-***-' + s[-4:]
          return suf if cnt == 0 else f'+{"*" * cnt}-{suf}'
  
  

• func maskPII(s string) string {
  	i := strings.Index(s, "@")
  	if i != -1 {
  		s = strings.ToLower(s)
  		return s[0:1] + "*****" + s[i-1:]
  	}
  	t := []rune{}
  	for _, c := range s {
  		if c >= '0' && c <= '9' {
  			t = append(t, c)
  		}
  	}
  	s = string(t)
  	cnt := len(s) - 10
  	suf := "***-***-" + s[len(s)-4:]
  	if cnt == 0 {
  		return suf
  	}
  	return "+" + strings.Repeat("*", cnt) + "-" + suf
  }
  

• function maskPII(s: string): string {
      const i = s.indexOf('@');
      if (i !== -1) {
          let ans = s[0].toLowerCase() + '*****';
          for (let j = i - 1; j < s.length; ++j) {
              ans += s.charAt(j).toLowerCase();
          }
          return ans;
      }
      let t = '';
      for (const c of s) {
          if (/\d/.test(c)) {
              t += c;
          }
      }
      const cnt = t.length - 10;
      const suf = `***-***-${t.substring(t.length - 4)}`;
      return cnt === 0 ? suf : `+${'*'.repeat(cnt)}-${suf}`;
  }
  
  

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