Formatted question description: https://leetcode.ca/all/681.html
681. Next Closest Time
Level
Medium
Description
Given a time represented in the format “HH:MM”, form the next closest time by reusing the current digits. There is no limit on how many times a digit can be reused.
You may assume the given input string is always valid. For example, “01:34”, “12:09” are all valid. “1:34”, “12:9” are all invalid.
Example 1:
Input: “19:34”
Output: “19:39”
Explanation: The next closest time choosing from digits 1, 9, 3, 4, is 19:39, which occurs 5 minutes later. It is not 19:33, because this occurs 23 hours and 59 minutes later.
Example 2:
Input: “23:59”
Output: “22:22”
Explanation: The next closest time choosing from digits 2, 3, 5, 9, is 22:22. It may be assumed that the returned time is next day’s time since it is smaller than the input time numerically.
Solution
Simulate all possible times minute by minute. If a time can be formed by reusing the current digit, return the time.
When returning the time, use String.format to convert it into the required format “HH:MM”.
class Solution {
public String nextClosestTime(String time) {
String hourStr = time.substring(0, 2), minuteStr = time.substring(3);
Set<Integer> set = new HashSet<Integer>();
for (int i = 0; i < 2; i++) {
set.add(hourStr.charAt(i) - '0');
set.add(minuteStr.charAt(i) - '0');
}
int[] timeArray = {Integer.parseInt(hourStr), Integer.parseInt(minuteStr)};
for (int i = 1; i <= 1440; i++) {
next(timeArray);
if (isReuse(timeArray, set)) {
String nextTime = String.format("%02d:%02d", timeArray[0], timeArray[1]);
return nextTime;
}
}
return time;
}
public void next(int[] timeArray) {
timeArray[1]++;
if (timeArray[1] >= 60) {
timeArray[1] %= 60;
timeArray[0]++;
}
if (timeArray[0] >= 24)
timeArray[0] %= 24;
}
public boolean isReuse(int[] timeArray, Set<Integer> set) {
int hour = timeArray[0], minute = timeArray[1];
if (!set.contains(hour / 10))
return false;
else if (!set.contains(hour % 10))
return false;
else if (!set.contains(minute / 10))
return false;
else if (!set.contains(minute % 10))
return false;
else
return true;
}
}