# 677. Map Sum Pairs

## Description

Design a map that allows you to do the following:

• Maps a string key to a given value.
• Returns the sum of the values that have a key with a prefix equal to a given string.

Implement the MapSum class:

• MapSum() Initializes the MapSum object.
• void insert(String key, int val) Inserts the key-val pair into the map. If the key already existed, the original key-value pair will be overridden to the new one.
• int sum(string prefix) Returns the sum of all the pairs' value whose key starts with the prefix.

Example 1:

Input
["MapSum", "insert", "sum", "insert", "sum"]
[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]]
Output
[null, null, 3, null, 5]

Explanation
MapSum mapSum = new MapSum();
mapSum.insert("apple", 3);
mapSum.sum("ap");           // return 3 (apple = 3)
mapSum.insert("app", 2);
mapSum.sum("ap");           // return 5 (apple + app = 3 + 2 = 5)


Constraints:

• 1 <= key.length, prefix.length <= 50
• key and prefix consist of only lowercase English letters.
• 1 <= val <= 1000
• At most 50 calls will be made to insert and sum.

## Solutions

• class Trie {
private Trie[] children = new Trie[26];
private int val;

public void insert(String w, int x) {
Trie node = this;
for (int i = 0; i < w.length(); ++i) {
int idx = w.charAt(i) - 'a';
if (node.children[idx] == null) {
node.children[idx] = new Trie();
}
node = node.children[idx];
node.val += x;
}
}

public int search(String w) {
Trie node = this;
for (int i = 0; i < w.length(); ++i) {
int idx = w.charAt(i) - 'a';
if (node.children[idx] == null) {
return 0;
}
node = node.children[idx];
}
return node.val;
}
}

class MapSum {
private Map<String, Integer> d = new HashMap<>();
private Trie trie = new Trie();

public MapSum() {
}

public void insert(String key, int val) {
int x = val - d.getOrDefault(key, 0);
d.put(key, val);
trie.insert(key, x);
}

public int sum(String prefix) {
return trie.search(prefix);
}
}

/**
* Your MapSum object will be instantiated and called as such:
* MapSum obj = new MapSum();
* obj.insert(key,val);
* int param_2 = obj.sum(prefix);
*/

• class Trie {
public:
Trie()
: children(26, nullptr) {
}

void insert(string& w, int x) {
Trie* node = this;
for (char c : w) {
c -= 'a';
if (!node->children[c]) {
node->children[c] = new Trie();
}
node = node->children[c];
node->val += x;
}
}

int search(string& w) {
Trie* node = this;
for (char c : w) {
c -= 'a';
if (!node->children[c]) {
return 0;
}
node = node->children[c];
}
return node->val;
}

private:
vector<Trie*> children;
int val = 0;
};

class MapSum {
public:
MapSum() {
}

void insert(string key, int val) {
int x = val - d[key];
d[key] = val;
trie->insert(key, x);
}

int sum(string prefix) {
return trie->search(prefix);
}

private:
unordered_map<string, int> d;
Trie* trie = new Trie();
};

/**
* Your MapSum object will be instantiated and called as such:
* MapSum* obj = new MapSum();
* obj->insert(key,val);
* int param_2 = obj->sum(prefix);
*/

• class Trie:
def __init__(self):
self.children: List[Trie | None] = [None] * 26
self.val: int = 0

def insert(self, w: str, x: int):
node = self
for c in w:
idx = ord(c) - ord('a')
if node.children[idx] is None:
node.children[idx] = Trie()
node = node.children[idx]
node.val += x

def search(self, w: str) -> int:
node = self
for c in w:
idx = ord(c) - ord('a')
if node.children[idx] is None:
return 0
node = node.children[idx]
return node.val

class MapSum:
def __init__(self):
self.d = defaultdict(int)
self.tree = Trie()

def insert(self, key: str, val: int) -> None:
x = val - self.d[key]
self.d[key] = val
self.tree.insert(key, x)

def sum(self, prefix: str) -> int:
return self.tree.search(prefix)

# Your MapSum object will be instantiated and called as such:
# obj = MapSum()
# obj.insert(key,val)
# param_2 = obj.sum(prefix)


• type trie struct {
children [26]*trie
val      int
}

func (t *trie) insert(w string, x int) {
for _, c := range w {
c -= 'a'
if t.children[c] == nil {
t.children[c] = &trie{}
}
t = t.children[c]
t.val += x
}
}

func (t *trie) search(w string) int {
for _, c := range w {
c -= 'a'
if t.children[c] == nil {
return 0
}
t = t.children[c]
}
return t.val
}

type MapSum struct {
d map[string]int
t *trie
}

func Constructor() MapSum {
return MapSum{make(map[string]int), &trie{} }
}

func (this *MapSum) Insert(key string, val int) {
x := val - this.d[key]
this.d[key] = val
this.t.insert(key, x)
}

func (this *MapSum) Sum(prefix string) int {
return this.t.search(prefix)
}

/**
* Your MapSum object will be instantiated and called as such:
* obj := Constructor();
* obj.Insert(key,val);
* param_2 := obj.Sum(prefix);
*/

• class Trie {
children: Trie[];
val: number;

constructor() {
this.children = new Array(26);
this.val = 0;
}

insert(w: string, x: number) {
let node: Trie = this;
for (const c of w) {
const i = c.charCodeAt(0) - 97;
if (!node.children[i]) {
node.children[i] = new Trie();
}
node = node.children[i];
node.val += x;
}
}

search(w: string): number {
let node: Trie = this;
for (const c of w) {
const i = c.charCodeAt(0) - 97;
if (!node.children[i]) {
return 0;
}
node = node.children[i];
}
return node.val;
}
}

class MapSum {
d: Map<string, number>;
t: Trie;
constructor() {
this.d = new Map();
this.t = new Trie();
}

insert(key: string, val: number): void {
const x = val - (this.d.get(key) ?? 0);
this.d.set(key, val);
this.t.insert(key, x);
}

sum(prefix: string): number {
return this.t.search(prefix);
}
}

/**
* Your MapSum object will be instantiated and called as such:
* var obj = new MapSum()
* obj.insert(key,val)
* var param_2 = obj.sum(prefix)
*/