Formatted question description: https://leetcode.ca/all/633.html

# 633. Sum of Square Numbers

Easy

## Description

Given a non-negative integer c, your task is to decide whether there’re two integers a and b such that a2 + b2 = c.

Example 1:

Input: 5

Output: True

*Explanation: 1 * 1 + 2 * 2 = 5

Example 2:

Input: 3

Output: False

## Solution

Maintain two numbers low and high, which are 0 and the greatest integer less than or equal to the square root of c. While low < high, calculate sum = low * low + high * high. If sum == c, then the two integers are found, so return true. If sum > c, then sum is too large, so decrease high by 1. If sum < c, then sum is too small, so increase low by 1. If the two integers can’t be found, return false.

• class Solution {
public boolean judgeSquareSum(int c) {
int low = 0, high = (int) Math.sqrt(c);
while (low <= high) {
int sum = low * low + high * high;
if (sum == c)
return true;
else if (sum > c)
high--;
else
low++;
}
return false;
}
}

• Todo

• class Solution(object):
def judgeSquareSum(self, c):
"""
:type c: int
:rtype: bool
"""
n = int(c ** 0.5)
start = 0
end = n
while start <= end:
mid = start ** 2 + end ** 2
if mid == c:
return True
elif mid < c:
start += 1
else:
end -= 1
return False