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495. Teemo Attacking

Description

Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds. More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]. If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack.

You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration.

Return the total number of seconds that Ashe is poisoned.

 

Example 1:

Input: timeSeries = [1,4], duration = 2
Output: 4
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5.
Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.

Example 2:

Input: timeSeries = [1,2], duration = 2
Output: 3
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3.
Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.

 

Constraints:

• 1 <= timeSeries.length <= 104
• 0 <= timeSeries[i], duration <= 107
• timeSeries is sorted in non-decreasing order.

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• C#

• class Solution {
      public int findPoisonedDuration(int[] timeSeries, int duration) {
          int n = timeSeries.length;
          int ans = duration;
          for (int i = 1; i < n; ++i) {
              ans += Math.min(duration, timeSeries[i] - timeSeries[i - 1]);
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      int findPoisonedDuration(vector<int>& timeSeries, int duration) {
          int ans = duration;
          int n = timeSeries.size();
          for (int i = 1; i < n; ++i) {
              ans += min(duration, timeSeries[i] - timeSeries[i - 1]);
          }
          return ans;
      }
  };
  

• class Solution:
      def findPoisonedDuration(self, timeSeries: List[int], duration: int) -> int:
          ans = duration
          for a, b in pairwise(timeSeries):
              ans += min(duration, b - a)
          return ans
  
  

• func findPoisonedDuration(timeSeries []int, duration int) (ans int) {
  	ans = duration
  	for i, x := range timeSeries[1:] {
  		ans += min(duration, x-timeSeries[i])
  	}
  	return
  }
  

• function findPoisonedDuration(timeSeries: number[], duration: number): number {
      const n = timeSeries.length;
      let ans = duration;
      for (let i = 1; i < n; ++i) {
          ans += Math.min(duration, timeSeries[i] - timeSeries[i - 1]);
      }
      return ans;
  }
  
  

• public class Solution {
      public int FindPoisonedDuration(int[] timeSeries, int duration) {
          int ans = duration;
          int n = timeSeries.Length;
          for (int i = 1; i < n; ++i) {
              ans += Math.Min(duration, timeSeries[i] - timeSeries[i - 1]);
          }
          return ans;
      }
  }
  

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