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420. Strong Password Checker
Description
A password is considered strong if the below conditions are all met:
- It has at least
6
characters and at most20
characters. - It contains at least one lowercase letter, at least one uppercase letter, and at least one digit.
- It does not contain three repeating characters in a row (i.e.,
"Baaabb0"
is weak, but"Baaba0"
is strong).
Given a string password
, return the minimum number of steps required to make password
strong. if password
is already strong, return 0
.
In one step, you can:
- Insert one character to
password
, - Delete one character from
password
, or - Replace one character of
password
with another character.
Example 1:
Input: password = "a" Output: 5
Example 2:
Input: password = "aA1" Output: 3
Example 3:
Input: password = "1337C0d3" Output: 0
Constraints:
1 <= password.length <= 50
password
consists of letters, digits, dot'.'
or exclamation mark'!'
.
Solutions
-
class Solution { public int strongPasswordChecker(String password) { int types = countTypes(password); int n = password.length(); if (n < 6) { return Math.max(6 - n, 3 - types); } char[] chars = password.toCharArray(); if (n <= 20) { int replace = 0; int cnt = 0; char prev = '~'; for (char curr : chars) { if (curr == prev) { ++cnt; } else { replace += cnt / 3; cnt = 1; prev = curr; } } replace += cnt / 3; return Math.max(replace, 3 - types); } int replace = 0, remove = n - 20; int remove2 = 0; int cnt = 0; char prev = '~'; for (char curr : chars) { if (curr == prev) { ++cnt; } else { if (remove > 0 && cnt >= 3) { if (cnt % 3 == 0) { --remove; --replace; } else if (cnt % 3 == 1) { ++remove2; } } replace += cnt / 3; cnt = 1; prev = curr; } } if (remove > 0 && cnt >= 3) { if (cnt % 3 == 0) { --remove; --replace; } else if (cnt % 3 == 1) { ++remove2; } } replace += cnt / 3; int use2 = Math.min(Math.min(replace, remove2), remove / 2); replace -= use2; remove -= use2 * 2; int use3 = Math.min(replace, remove / 3); replace -= use3; remove -= use3 * 3; return (n - 20) + Math.max(replace, 3 - types); } private int countTypes(String s) { int a = 0, b = 0, c = 0; for (char ch : s.toCharArray()) { if (Character.isLowerCase(ch)) { a = 1; } else if (Character.isUpperCase(ch)) { b = 1; } else if (Character.isDigit(ch)) { c = 1; } } return a + b + c; } }
-
class Solution { public: int strongPasswordChecker(string password) { int types = countTypes(password); int n = password.size(); if (n < 6) return max(6 - n, 3 - types); if (n <= 20) { int replace = 0, cnt = 0; char prev = '~'; for (char& curr : password) { if (curr == prev) ++cnt; else { replace += cnt / 3; cnt = 1; prev = curr; } } replace += cnt / 3; return max(replace, 3 - types); } int replace = 0, remove = n - 20; int remove2 = 0; int cnt = 0; char prev = '~'; for (char& curr : password) { if (curr == prev) ++cnt; else { if (remove > 0 && cnt >= 3) { if (cnt % 3 == 0) { --remove; --replace; } else if (cnt % 3 == 1) ++remove2; } replace += cnt / 3; cnt = 1; prev = curr; } } if (remove > 0 && cnt >= 3) { if (cnt % 3 == 0) { --remove; --replace; } else if (cnt % 3 == 1) ++remove2; } replace += cnt / 3; int use2 = min(min(replace, remove2), remove / 2); replace -= use2; remove -= use2 * 2; int use3 = min(replace, remove / 3); replace -= use3; remove -= use3 * 3; return (n - 20) + max(replace, 3 - types); } int countTypes(string& s) { int a = 0, b = 0, c = 0; for (char& ch : s) { if (islower(ch)) a = 1; else if (isupper(ch)) b = 1; else if (isdigit(ch)) c = 1; } return a + b + c; } };
-
class Solution: def strongPasswordChecker(self, password: str) -> int: def countTypes(s): a = b = c = 0 for ch in s: if ch.islower(): a = 1 elif ch.isupper(): b = 1 elif ch.isdigit(): c = 1 return a + b + c types = countTypes(password) n = len(password) if n < 6: return max(6 - n, 3 - types) if n <= 20: replace = cnt = 0 prev = '~' for curr in password: if curr == prev: cnt += 1 else: replace += cnt // 3 cnt = 1 prev = curr replace += cnt // 3 return max(replace, 3 - types) replace = cnt = 0 remove, remove2 = n - 20, 0 prev = '~' for curr in password: if curr == prev: cnt += 1 else: if remove > 0 and cnt >= 3: if cnt % 3 == 0: remove -= 1 replace -= 1 elif cnt % 3 == 1: remove2 += 1 replace += cnt // 3 cnt = 1 prev = curr if remove > 0 and cnt >= 3: if cnt % 3 == 0: remove -= 1 replace -= 1 elif cnt % 3 == 1: remove2 += 1 replace += cnt // 3 use2 = min(replace, remove2, remove // 2) replace -= use2 remove -= use2 * 2 use3 = min(replace, remove // 3) replace -= use3 remove -= use3 * 3 return n - 20 + max(replace, 3 - types)