Formatted question description: https://leetcode.ca/all/399.html
399 Evaluate Division Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example: Given a / b = 2.0, b / c = 3.0. queries are: a / c = ?, b / a = ?, a / e = ?, a / a = ?, x / x = ? . return [6.0, 0.5, -1.0, 1.0, -1.0 ]. The input is: vector<pair<string, string>> equations, vector<double>& values, vector<pair<string, string>> queries , where equations.size() == values.size(), and the values are positive. This represents the equations. Return vector<double>. According to the example above: equations = [ ["a", "b"], ["b", "c"] ], values = [2.0, 3.0], queries = [ ["a", "c"], ["b", "a"], ["a", "e"], ["a", "a"], ["x", "x"] ]. The input is always valid. You may assume that evaluating the queries will result in no division by zero and there is no contradiction. @tag-graph
Need a HashSet to record the expressions that have been visited, and then call a recursive function on it.
In the recursive function, we quickly find the expression in the HashMap,
- If it is equal to a known expression, return the result directly.
- If not, then we need to look for it indirectly. We traverse the known conditions in the HashMap that are the same as the numerator in the analytic formula, skip the ones that have been traversed before, or add the visited array, and then call the recursive function.
- If the return value is a positive number, it will be multiplied by the value of the current known condition and returned, similar to the case 1 above. After the multiplication, b will be eliminated.
- If it is known that no solution is found, -1 will be returned at the end