# Question

Formatted question description: https://leetcode.ca/all/396.html

```
Given an array of integers A and let n to be its length.
Assume Bk to be an array obtained by rotating the array A k positions clock-wise,
we define a "rotation function" F on A as follow:
F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1].
Calculate the maximum value of F(0), F(1), ..., F(n-1).
Note:
n is guaranteed to be less than 105.
Example:
A = [4, 3, 2, 6]
F(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18 = 25
F(1) = (0 * 6) + (1 * 4) + (2 * 3) + (3 * 2) = 0 + 4 + 6 + 6 = 16
F(2) = (0 * 2) + (1 * 6) + (2 * 4) + (3 * 3) = 0 + 6 + 8 + 9 = 23
F(3) = (0 * 3) + (1 * 2) + (2 * 6) + (3 * 4) = 0 + 2 + 12 + 12 = 26
So the maximum value of F(0), F(1), F(2), F(3) is F(3) = 26.
@tag-array
```

# Algorithm

Abstract the concrete numbers as A, B, C, D, then we can get:

```
F(0) = 0A + 1B + 2C +3D
F(1) = 0D + 1A + 2B +3C
F(2) = 0C + 1D + 2A +3B
F(3) = 0B + 1C + 2D +3A
```

Then, through careful observation, we can draw the following law:

```
sum = 1A + 1B + 1C + 1D
F(1) = F(0) + sum-4D
F(2) = F(1) + sum-4C
F(3) = F(2) + sum-4B
```

Then we have found the rule, `F(i) = F(i-1) + sum-n*A[n-i]`

# Code

Java