Welcome to Subscribe On Youtube

Question

Formatted question description: https://leetcode.ca/all/293.html

 293	Flip Game

 You are playing the following Flip Game with your friend:
    Given a string that contains only these two characters: + and -,
    you and your friend take turns to flip two-consecutive "++" into "--".

 The game ends when a person can no longer make a move and therefore the other person will be the winner.

 Write a function to compute all possible states of the string after one valid move.

 For example, given s = "++++", after one move, it may become one of the following states:
 (input string可以有'-',比如"+++--++")

 [
   "--++",
   "+--+",
   "++--"
 ]

 If there is no valid move, return an empty list [].

Algorithm

Start traversing from the second letter, each time it is judged whether the current letter is +, and the previous letter is +, if both are plus, the reversed string will be stored in the result.

Code

  • import java.util.ArrayList;
    import java.util.List;
    
    public class Flip_Game {
        public class Solution {
            public List<String> generatePossibleNextMoves(String s) {
                List<String> result = new ArrayList<>();
                char[] arr = s.toCharArray();
    
                // solution-1: restore
                for(int i = 1; i < s.length(); i++) {
                    if(arr[i] == '+' && arr[i - 1] == '+') {
                        arr[i] = '-';
                        arr[i - 1] = '-';
                        result.add(String.valueOf(arr));
                        arr[i] = '+'; // @note: need to resulttore
                        arr[i - 1] = '+';
                    }
                }
    
                // solution-2: just concatenate, no restore
                for(int i = 1; i < s.length(); i++) {
                    if(arr[i] == '+' && arr[i - 1] == '+') {
                        result.add(s.substring(0, i - 1) + "--" + s.substring(i + 1));
                    }
                }
    
                return result;
            }
        }
    }
    
    ############
    
    class Solution {
        public List<String> generatePossibleNextMoves(String currentState) {
            char[] cs = currentState.toCharArray();
            List<String> ans = new ArrayList<>();
            for (int i = 0; i < cs.length - 1; ++i) {
                if (cs[i] == '+' && cs[i + 1] == '+') {
                    cs[i] = '-';
                    cs[i + 1] = '-';
                    ans.add(String.valueOf(cs));
                    cs[i] = '+';
                    cs[i + 1] = '+';
                }
            }
            return ans;
        }
    }
    
  • // OJ: https://leetcode.com/problems/flip-game/
    // Time: O(N)
    // Space: O(1)
    class Solution {
    public:
        vector<string> generatePossibleNextMoves(string s) {
            vector<string> ans;
            for (int i = 1, N = s.size(); i < N; ++i) {
                if (s[i] != '+' || s[i - 1] != '+') continue;
                ans.push_back(s);
                ans.back()[i] = ans.back()[i - 1] = '-';
            }
            return ans;
        }
    };
    
  • class Solution(object):
      def generatePossibleNextMoves(self, s):
        """
        :type s: str
        :rtype: List[str]
        """
        ans = []
        for i in range(0, len(s) - 1):
          if s[i:i + 2] == "++":
            ans.append(s[:i] + "--" + s[i + 2:])
        return ans
    
    ############
    
    class Solution:
        def generatePossibleNextMoves(self, currentState: str) -> List[str]:
            s = list(currentState)
            ans = []
            for i, c in enumerate(s[:-1]):
                if c == "+" and s[i + 1] == "+":
                    s[i] = s[i + 1] = "-"
                    ans.append("".join(s))
                    s[i] = s[i + 1] = "+"
            return ans
    
    
  • func generatePossibleNextMoves(currentState string) []string {
    	ans := []string{}
    	cs := []byte(currentState)
    	for i, c := range cs[1:] {
    		if c == '+' && cs[i] == '+' {
    			cs[i], cs[i+1] = '-', '-'
    			ans = append(ans, string(cs))
    			cs[i], cs[i+1] = '+', '+'
    		}
    	}
    	return ans
    }
    

All Problems

All Solutions