Welcome to Subscribe On Youtube

284. Peeking Iterator

Description

Design an iterator that supports the peek operation on an existing iterator in addition to the hasNext and the next operations.

Implement the PeekingIterator class:

  • PeekingIterator(Iterator<int> nums) Initializes the object with the given integer iterator iterator.
  • int next() Returns the next element in the array and moves the pointer to the next element.
  • boolean hasNext() Returns true if there are still elements in the array.
  • int peek() Returns the next element in the array without moving the pointer.

Note: Each language may have a different implementation of the constructor and Iterator, but they all support the int next() and boolean hasNext() functions.

 

Example 1:

Input
["PeekingIterator", "next", "peek", "next", "next", "hasNext"]
[[[1, 2, 3]], [], [], [], [], []]
Output
[null, 1, 2, 2, 3, false]

Explanation
PeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [1,2,3]
peekingIterator.next();    // return 1, the pointer moves to the next element [1,2,3].
peekingIterator.peek();    // return 2, the pointer does not move [1,2,3].
peekingIterator.next();    // return 2, the pointer moves to the next element [1,2,3]
peekingIterator.next();    // return 3, the pointer moves to the next element [1,2,3]
peekingIterator.hasNext(); // return False

 

Constraints:

  • 1 <= nums.length <= 1000
  • 1 <= nums[i] <= 1000
  • All the calls to next and peek are valid.
  • At most 1000 calls will be made to next, hasNext, and peek.

 

Follow up: How would you extend your design to be generic and work with all types, not just integer?

Solutions

  • // Java Iterator interface reference:
    // https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html
    
    class PeekingIterator implements Iterator<Integer> {
        private Iterator<Integer> iterator;
        private boolean hasPeeked;
        private Integer peekedElement;
    
        public PeekingIterator(Iterator<Integer> iterator) {
            // initialize any member here.
            this.iterator = iterator;
        }
    
        // Returns the next element in the iteration without advancing the iterator.
        public Integer peek() {
            if (!hasPeeked) {
                peekedElement = iterator.next();
                hasPeeked = true;
            }
            return peekedElement;
        }
    
        // hasNext() and next() should behave the same as in the Iterator interface.
        // Override them if needed.
        @Override
        public Integer next() {
            if (!hasPeeked) {
                return iterator.next();
            }
            Integer result = peekedElement;
            hasPeeked = false;
            peekedElement = null;
            return result;
        }
    
        @Override
        public boolean hasNext() {
            return hasPeeked || iterator.hasNext();
        }
    }
    
  • /*
     * Below is the interface for Iterator, which is already defined for you.
     * **DO NOT** modify the interface for Iterator.
     *
     *  class Iterator {
     *		struct Data;
     * 		Data* data;
     *  public:
     *		Iterator(const vector<int>& nums);
     * 		Iterator(const Iterator& iter);
     *
     * 		// Returns the next element in the iteration.
     *		int next();
     *
     *		// Returns true if the iteration has more elements.
     *		bool hasNext() const;
     *	};
     */
    
    class PeekingIterator : public Iterator {
    public:
        PeekingIterator(const vector<int>& nums)
            : Iterator(nums) {
            // Initialize any member here.
            // **DO NOT** save a copy of nums and manipulate it directly.
            // You should only use the Iterator interface methods.
            hasPeeked = false;
        }
    
        // Returns the next element in the iteration without advancing the iterator.
        int peek() {
            if (!hasPeeked) {
                peekedElement = Iterator::next();
                hasPeeked = true;
            }
            return peekedElement;
        }
    
        // hasNext() and next() should behave the same as in the Iterator interface.
        // Override them if needed.
        int next() {
            if (!hasPeeked) return Iterator::next();
            hasPeeked = false;
            return peekedElement;
        }
    
        bool hasNext() const {
            return hasPeeked || Iterator::hasNext();
        }
    
    private:
        bool hasPeeked;
        int peekedElement;
    };
    
  • # Below is the interface for Iterator, which is already defined for you.
    #
    # class Iterator:
    #     def __init__(self, nums):
    #         """
    #         Initializes an iterator object to the beginning of a list.
    #         :type nums: List[int]
    #         """
    #
    #     def hasNext(self):
    #         """
    #         Returns true if the iteration has more elements.
    #         :rtype: bool
    #         """
    #
    #     def next(self):
    #         """
    #         Returns the next element in the iteration.
    #         :rtype: int
    #         """
    
    
    class PeekingIterator:
        def __init__(self, iterator):
            """
            Initialize your data structure here.
            :type iterator: Iterator
            """
            self.iterator = iterator
            self.has_peeked = False
            self.peeked_element = None
    
        def peek(self):
            """
            Returns the next element in the iteration without advancing the iterator.
            :rtype: int
            """
            if not self.has_peeked:
                self.peeked_element = self.iterator.next()
                self.has_peeked = True
            return self.peeked_element
    
        def next(self):
            """
            :rtype: int
            """
            if not self.has_peeked:
                return self.iterator.next()
            result = self.peeked_element
            self.has_peeked = False
            self.peeked_element = None
            return result
    
        def hasNext(self):
            """
            :rtype: bool
            """
            return self.has_peeked or self.iterator.hasNext()
    
    
    # Your PeekingIterator object will be instantiated and called as such:
    # iter = PeekingIterator(Iterator(nums))
    # while iter.hasNext():
    #     val = iter.peek()   # Get the next element but not advance the iterator.
    #     iter.next()         # Should return the same value as [val].
    
    
  • /*   Below is the interface for Iterator, which is already defined for you.
     *
     *   type Iterator struct {
     *
     *   }
     *
     *   func (this *Iterator) hasNext() bool {
     *		// Returns true if the iteration has more elements.
     *   }
     *
     *   func (this *Iterator) next() int {
     *		// Returns the next element in the iteration.
     *   }
     */
    
    type PeekingIterator struct {
    	iter          *Iterator
    	hasPeeked     bool
    	peekedElement int
    }
    
    func Constructor(iter *Iterator) *PeekingIterator {
    	return &PeekingIterator{iter, iter.hasNext(), iter.next()}
    }
    
    func (this *PeekingIterator) hasNext() bool {
    	return this.hasPeeked || this.iter.hasNext()
    }
    
    func (this *PeekingIterator) next() int {
    	if !this.hasPeeked {
    		return this.iter.next()
    	}
    	this.hasPeeked = false
    	return this.peekedElement
    }
    
    func (this *PeekingIterator) peek() int {
    	if !this.hasPeeked {
    		this.peekedElement = this.iter.next()
    		this.hasPeeked = true
    	}
    	return this.peekedElement
    }
    

All Problems

All Solutions