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181. Employees Earning More Than Their Managers

Description

Table: Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.

 

Write a solution to find the employees who earn more than their managers.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Employee table:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
Output: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
Explanation: Joe is the only employee who earns more than his manager.

Solutions

• Python
• SQL

• import pandas as pd
  
  
  def find_employees(employee: pd.DataFrame) -> pd.DataFrame:
      df = employee.merge(right=employee, how="left", left_on="managerId", right_on="id")
      emp = df[df["salary_x"] > df["salary_y"]]["name_x"]
  
      return pd.DataFrame({"Employee": emp})
  
  

• SELECT e1.Name FROM Employee e1
  JOIN Employee e2 ON e1.ManagerId = e2.Id
  WHERE e1.Salary > e2.Salary;
  
  --
  
  SELECT e1.Name FROM Employee e1, Employee e2
  WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;
  
  --
  
  SELECT Name AS Employee
  FROM Employee AS Curr
  WHERE
      Salary > (
          SELECT Salary
          FROM Employee
          WHERE Id = Curr.ManagerId
      );
  
  

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